Part f only 2. Use the equation to solve the following problems:SODIUM PHOSPHATE + SILVER NITRATE →a. What type of reaction is this?b. How many moles of sodium phosphate would be required to react with 1.0 mol of silver nitrate?c. How many moles of sodium nitrate can be produced from 0.50 mol of sodium phosphate?d. How many grams of silver phosphate can be produced from 5.00 g of sodium phosphate?e. If you have 9.44 g of sodium phosphate, how many grams of silver nitrate will be needed to complete thereaction?f. If you have 4.00 grams of each of the reactants, how many grams of each will be present at the end of thereaction?g. When 4.00 g of silver nitrate are reacted with excess sodium phosphate, 2.11 g of silver phosphate areproduced. What is the percent yield of silver phosphate?

A limiting reagent is a species which is consumed completely during the reaction. It determines the overall yield of the reaction.In first step, we write balanced chemical equation taking place.Next we write molar mass of each of the compounds.Next, we calculate stoichiometric mass by multiplying molar mass with the coefficient present in balanced chemical equation.Finally, using unitary method we obtained mass of sodium phosphate required to react with silver nitrate.This shows silver nitrate is limiting reagent and sodium phosphate is excess reagent.A limiting reagent is a species which is consumed completely during the reaction. It determines the overall yield of the reaction.Silver nitrate left : 0 g sodium phosphate left : 2.71 g

Answered: f. If you have 4.00 grams of each of…

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f. If you have 4.00 grams of each of the reactants, how many grams of each will be present at the end of the reaction?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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