Answer everything **Title: Osmosis Experiment: Glucose Solution in Dialysis Tubing****Experiment Objective:**For an experiment on osmosis, some dialysis tubing (a semi-permeable membrane) is filled with 750 mL of a glucose (C6H12O6, non-electrolyte) solution (glucose cannot pass through the membrane). If the reaction is carried out at 36.5°C and creates an osmotic pressure of 1.75 atm, what would be the concentration of the glucose solution?**Key Calculations and Formulas:**1. **Formula for Osmotic Pressure (π):** \[\pi = MRT\] Where, - \(\pi\) = osmotic pressure (in atm) - \(M\) = molarity of the solution (in mol/L) - \(R\) = gas constant (0.0821 L·atm/(K·mol)) - \(T\) = temperature (in Kelvin)2. **Converting Celsius to Kelvin:** \[ T(K) = T(°C) + 273 \] For 36.5°C: \[ 36.5 + 273 = 309.5 \, K \]3. **Rearranging the Osmotic Pressure Formula to Solve for Molarity (M):** \[ M = \frac{\pi}{RT} \]**Given Data:**- Osmotic Pressure (π) = 1.75 atm- Gas Constant (R) = 0.0821 L·atm/(K·mol)- Temperature (T) = 36.5°C = 309.5 K **Calculation Steps:**1. Substitute the values into the rearranged formula: \[ M = \frac{1.75 \, \text{atm}}{0.0821 \, \text{L·atm/(K·mol)} \times 309.5 \, \text{K}} \]2. Perform the calculation: \[ M = \frac{1.75}{0.0821 \times 309.5} \]3. Simplify the calculation to find the molarity (M): \[ M = 0.0686 \, \text{mol/L} \]

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Science

Chemistry

f ti a

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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