Φ Obtain the integral that will solve for the total charge Q given p=10(r-4) (r-5) cos (0) sin C/m³ and the limits are as follows: 4≤r≤ 5,0° ≤ 0 ≤ 25°, 0.9л ≤ ≤1.1a. Q=10 1.1z p=0.9 [M] must be ✓ [M] =? 25° 5 ³ 0=0º [M] drdodd r=4 A. B. C. D. E. 10(-4) (r-5) cos (0) sin Sin() (r-4) (r-5) cos (0) sin (4) 2 (r−4) (r— 5) r² cos (0) sin(0) sin F. None of the choices 10(r-4) (r−5) r² cos (0) sin(0) sin (1) 10(r-4) (r-5) r² cos (0) sin(0) sin in (1/2) (10-9)
Φ Obtain the integral that will solve for the total charge Q given p=10(r-4) (r-5) cos (0) sin C/m³ and the limits are as follows: 4≤r≤ 5,0° ≤ 0 ≤ 25°, 0.9л ≤ ≤1.1a. Q=10 1.1z p=0.9 [M] must be ✓ [M] =? 25° 5 ³ 0=0º [M] drdodd r=4 A. B. C. D. E. 10(-4) (r-5) cos (0) sin Sin() (r-4) (r-5) cos (0) sin (4) 2 (r−4) (r— 5) r² cos (0) sin(0) sin F. None of the choices 10(r-4) (r−5) r² cos (0) sin(0) sin (1) 10(r-4) (r-5) r² cos (0) sin(0) sin in (1/2) (10-9)
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Obtain the integral that will solve for the total charge Q given p = 10(r-4) (r-5) cos (0) sin C/m³ and the limits are as follows:
2
4≤r≤5,0⁰ ≤ 0≤25°, 0.9 ≤ ≤ 1.1л.
5
of 21.²² £2²50 p²
p=0.9 00⁰ r=4
Q=10
[M] must be
✓ [M] =?
[M] drdodd
A.
B.
D.
E.
10(r-4) (r-5) cos (0) sin
(r-4) (r-5) cos (0) sin
C.
(r− 4) (r − 5) r² cos (0) sin() sin
in (2)
Φ
10(r-4) (r - 5) r² cos (0) sin(0) sin
2
F. None of the choices
10(-4) (r-5) r² cos (0) sin() sin
()
(10-⁹)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2af8a093-22cb-4b73-8024-b8968cd71181%2F8438bc6c-ab04-4e51-8e20-8a751921704d%2F0nq19xk_processed.png&w=3840&q=75)
Transcribed Image Text:Φ
Obtain the integral that will solve for the total charge Q given p = 10(r-4) (r-5) cos (0) sin C/m³ and the limits are as follows:
2
4≤r≤5,0⁰ ≤ 0≤25°, 0.9 ≤ ≤ 1.1л.
5
of 21.²² £2²50 p²
p=0.9 00⁰ r=4
Q=10
[M] must be
✓ [M] =?
[M] drdodd
A.
B.
D.
E.
10(r-4) (r-5) cos (0) sin
(r-4) (r-5) cos (0) sin
C.
(r− 4) (r − 5) r² cos (0) sin() sin
in (2)
Φ
10(r-4) (r - 5) r² cos (0) sin(0) sin
2
F. None of the choices
10(-4) (r-5) r² cos (0) sin() sin
()
(10-⁹)
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