E = Eox cos(wt)az + Eoy cos(wt + 8)ay %3D a) Why is the 8 in the equation? b) Suppose Eox = Eoy = E, = 1 For this case, plot the magnitude and direction of the electric field vector in the x-y plane for [0. ππ3π - 5п Зп 7п ', 2n radians wt = 4'2 4 4 2 4 Or wt = [0,45,90,135,180,225,270,315,360] degrees And 8 = 0 i) 8 = -" ii)
E = Eox cos(wt)az + Eoy cos(wt + 8)ay %3D a) Why is the 8 in the equation? b) Suppose Eox = Eoy = E, = 1 For this case, plot the magnitude and direction of the electric field vector in the x-y plane for [0. ππ3π - 5п Зп 7п ', 2n radians wt = 4'2 4 4 2 4 Or wt = [0,45,90,135,180,225,270,315,360] degrees And 8 = 0 i) 8 = -" ii)
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![É = Eox cos(wt)ax + Eoy cos(wt + 8)ay
a) Why is the 8 in the equation?
b) Suppose
Eox = Eov = E, = 1
Ох
For this case, plot the magnitude and direction of the electric field vector in
the x-y plane for
5п Зп 7т
T,
4
π π3π
wt =
4'?'7,2 radians
4
Or
wt = [0,45,90,135,180,225,270,315,360] degrees
And
i)
ii)
8 = 0
8 =
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdb6e49c2-d01d-4438-a99a-92f670cec770%2F0bd7a40b-c51b-4ac0-a169-13ca8cbf7cf1%2Ff0et5mo_processed.png&w=3840&q=75)
Transcribed Image Text:É = Eox cos(wt)ax + Eoy cos(wt + 8)ay
a) Why is the 8 in the equation?
b) Suppose
Eox = Eov = E, = 1
Ох
For this case, plot the magnitude and direction of the electric field vector in
the x-y plane for
5п Зп 7т
T,
4
π π3π
wt =
4'?'7,2 radians
4
Or
wt = [0,45,90,135,180,225,270,315,360] degrees
And
i)
ii)
8 = 0
8 =
2
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