3) Use the differential form of Gauss's Law (V.Ē = 2 ) to find the chargeEodensity and then integrate over the volume to find the charge enclosed A closed surface with dimensionsa = b = 0.400 m and c = 0.800 m is located asshown in the figure below. The left edge of theDーXclosed surface is located at position x = a. Theelectric field throughout the region is non-uniform and given byE. = [k (xy?) î + k (x?y)j] N/C,where x,y are in meters, k =5.00 m3

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Answered: A closed surface with dimensions a = b…

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