F) Graph: 6x – 3y + 12 = 0 구 4 2. -8 -7 -6 -$ -4 -3 -2 -1 2 3 4 6. 7 8 -1 -2 -3 -4 -5 -7
F) Graph: 6x – 3y + 12 = 0 구 4 2. -8 -7 -6 -$ -4 -3 -2 -1 2 3 4 6. 7 8 -1 -2 -3 -4 -5 -7
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
answer graphing question
![**Graphing Linear Equations: An Example**
The graph represents the equation:
**6x - 3y + 12 = 0**
**Graph Details:**
- The graph is on a coordinate plane with both x and y axes labeled from -8 to 8.
- The line graph is expected to intersect the axes, showing the relationship between x and y as described by the equation.
**Equation Explanation:**
- This is a linear equation in standard form: Ax + By + C = 0.
- To graph it, you can find the intercepts:
- **X-intercept:** Set \(y = 0\): \(6x + 12 = 0 \rightarrow x = -2\)
- **Y-intercept:** Set \(x = 0\): \(-3y + 12 = 0 \rightarrow y = 4\)
- Plot these intercept points (-2, 0) and (0, 4) on the graph and draw a line through them to represent the equation.
This exercise demonstrates graphing a linear equation by finding x and y intercepts and using them to define the line on a coordinate plane.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F86c8cfd9-4a92-4a9d-9228-8676092022d2%2Ffe57282a-979d-4702-b06a-d55926404f77%2Foawu8kr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Graphing Linear Equations: An Example**
The graph represents the equation:
**6x - 3y + 12 = 0**
**Graph Details:**
- The graph is on a coordinate plane with both x and y axes labeled from -8 to 8.
- The line graph is expected to intersect the axes, showing the relationship between x and y as described by the equation.
**Equation Explanation:**
- This is a linear equation in standard form: Ax + By + C = 0.
- To graph it, you can find the intercepts:
- **X-intercept:** Set \(y = 0\): \(6x + 12 = 0 \rightarrow x = -2\)
- **Y-intercept:** Set \(x = 0\): \(-3y + 12 = 0 \rightarrow y = 4\)
- Plot these intercept points (-2, 0) and (0, 4) on the graph and draw a line through them to represent the equation.
This exercise demonstrates graphing a linear equation by finding x and y intercepts and using them to define the line on a coordinate plane.
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