F =75 kN The journal bearings at A and D exert only x and z components of force on the shaft. Determine the shaft's diameter to the nearest millimeter so that it can resist the loadings without exceeding an allowable: 100 mm (Radius) 200 mm B 150mm (Radium a) Shear stress of Tallow= 80 MPa. 250 mm D b) Von Mises stress of oallow = 200 MPa. VF =5 kN %3D 300 mm Note: According to the maximum distortion energy theory of failure: 1 4 C = -2 (4M² + 3T²) T2
F =75 kN The journal bearings at A and D exert only x and z components of force on the shaft. Determine the shaft's diameter to the nearest millimeter so that it can resist the loadings without exceeding an allowable: 100 mm (Radius) 200 mm B 150mm (Radium a) Shear stress of Tallow= 80 MPa. 250 mm D b) Von Mises stress of oallow = 200 MPa. VF =5 kN %3D 300 mm Note: According to the maximum distortion energy theory of failure: 1 4 C = -2 (4M² + 3T²) T2
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![F =75 kN
The journal bearings at A and D exert only x
and z components of force on the shaft.
Determine the shaft's diameter to the
nearest millimeter so that it can resist the
loadings without exceeding an allowable:
100 mm (Radius)
200 mm
B
150mm (Radius)
a) Shear stress of tallow= 80 MPa.
250 mm
b) Von Mises stress of oallow = 200 MPa.
F. =5 kN
300 mm
Note: According to the maximum distortion energy theory of failure:
1
4
(4M² + 3T2)
C =
Tállow2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F666c0810-d4fe-493a-94ee-3b49b10e3cdb%2Fc4691561-ada7-4eb5-b35f-c1b396f57e71%2F08cdsid_processed.jpeg&w=3840&q=75)
Transcribed Image Text:F =75 kN
The journal bearings at A and D exert only x
and z components of force on the shaft.
Determine the shaft's diameter to the
nearest millimeter so that it can resist the
loadings without exceeding an allowable:
100 mm (Radius)
200 mm
B
150mm (Radius)
a) Shear stress of tallow= 80 MPa.
250 mm
b) Von Mises stress of oallow = 200 MPa.
F. =5 kN
300 mm
Note: According to the maximum distortion energy theory of failure:
1
4
(4M² + 3T2)
C =
Tállow2
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