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Ey(x,t) = Eo cos[(6 rad/s)t] B₂(x,t) = Bocos[(6 rad/s)t] Ey(x,t) = Eo cos[(2 m¯¹)x] B₂(x,t) = Bo sin[(2 m-1)x] ○ A) ○ B) Ey(x,t) = Eo Bz(x,t) = Bo E,(x,t) B(x,t) Ey(x,t) = Eo cos[(2 m¹)x - (6 rad/s)] B₂(x,t) = Bocos[(2 m¹)x - (6 rad/s)] E) ○ D) Eo cos[(2 m)x(6 rad/s)t + x/2] Bocos[(2 m)x-(6 rad/s)r] Ey(x,t) = Eo cos[(2 m)x - (6 rad/s)r] B₂(x,t) =Bocos[(6 m¯¹)x - (2 rad/s)] ○ F)

Ey(x,t) = Eo cos[(6 rad/s)t] B₂(x,t) = Bocos[(6 rad/s)t] Ey(x,t) = Eo cos[(2 m¯¹)x] B₂(x,t) = Bo sin[(2 m-1)x] ○ A) ○ B) Ey(x,t) = Eo Bz(x,t) = Bo E,(x,t) B(x,t) Ey(x,t) = Eo cos[(2 m¹)x - (6 rad/s)] B₂(x,t) = Bocos[(2 m¹)x - (6 rad/s)] E) ○ D) Eo cos[(2 m)x(6 rad/s)t + x/2] Bocos[(2 m)x-(6 rad/s)r] Ey(x,t) = Eo cos[(2 m)x - (6 rad/s)r] B₂(x,t) =Bocos[(6 m¯¹)x - (2 rad/s)] ○ F)

Modern Physics
Modern Physics
3rd Edition
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Chapter13: Nuclear Structure
Section: Chapter Questions
Problem 59P
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Which pair of electric and magnetic field equations corresponds to an electromagnetic wave in a vacuum?

Ey(x,t) = Eo cos[(6 rad/s)t] B₂(x,t) = Bocos[(6 rad/s)t] Ey(x,t) = Eo cos[(2 m¯¹)x] B₂(x,t) = Bo sin[(2 m-1)x] ○ A) ○ B) Ey(x,t) = Eo Bz(x,t) = Bo E,(x,t) B(x,t) Ey(x,t) = Eo cos[(2 m¹)x - (6 rad/s)] B₂(x,t) = Bocos[(2 m¹)x - (6 rad/s)] E) ○ D) Eo cos[(2 m)x(6 rad/s)t + x/2] Bocos[(2 m)x-(6 rad/s)r] Ey(x,t) = Eo cos[(2 m)x - (6 rad/s)r] B₂(x,t) =Bocos[(6 m¯¹)x - (2 rad/s)] ○ F)
Transcribed Image Text:Ey(x,t) = Eo cos[(6 rad/s)t] B₂(x,t) = Bocos[(6 rad/s)t] Ey(x,t) = Eo cos[(2 m¯¹)x] B₂(x,t) = Bo sin[(2 m-1)x] ○ A) ○ B) Ey(x,t) = Eo Bz(x,t) = Bo E,(x,t) B(x,t) Ey(x,t) = Eo cos[(2 m¹)x - (6 rad/s)] B₂(x,t) = Bocos[(2 m¹)x - (6 rad/s)] E) ○ D) Eo cos[(2 m)x(6 rad/s)t + x/2] Bocos[(2 m)x-(6 rad/s)r] Ey(x,t) = Eo cos[(2 m)x - (6 rad/s)r] B₂(x,t) =Bocos[(6 m¯¹)x - (2 rad/s)] ○ F)
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