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(extrem ortant), health benefits as a job characteristic. The sample mean rating was 4.08, and the sample standard ation was 0.5. Test at the 10% significance level the null hypothesis that the population mean rating is at r inst the alternative that it is larger than 4. Click the icon to view the upper critical values of the Student's t distribution. at are the null and alternative hypotheses for this test? A. H₂: H=4 H₁: μ#4 C. Ho: ≤4 H₂>4 OB. H: 24 H₁: μ<4 OD. Ho: H=4 H. u=408

(extrem ortant), health benefits as a job characteristic. The sample mean rating was 4.08, and the sample standard ation was 0.5. Test at the 10% significance level the null hypothesis that the population mean rating is at r inst the alternative that it is larger than 4. Click the icon to view the upper critical values of the Student's t distribution. at are the null and alternative hypotheses for this test? A. H₂: H=4 H₁: μ#4 C. Ho: ≤4 H₂>4 OB. H: 24 H₁: μ<4 OD. Ho: H=4 H. u=408

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A random sample of 171 marketing students was asked to rate, on a scale from 1 (not important) to 5 (extremely important), health benefits as a job characteristic. The sample mean rating was 4.08, and the sample standard deviation was 0.5. Test at the 10% significance level the null hypothesis that the population mean rating is at most 4 against the alternative that it is larger than 4. Click the icon to view the upper critical values of the Student's t distribution. What are the null and alternative hypotheses for this test? OA. H₂: H=4 H₁: μ#4 OC. Ho: ≤4 H₁: μ>4 O A. Reject H₂ if OB. Reject Ho if OC. Reject H if For this test at the significance level x with sample mean x, hypothesized mean μo, sample standard deviations, and sample size n, what is the form of the decision rule? x-Ho s/√n x-Ho s/√√n x - Ho s/√√n X-Ho s/√n <-tn-la <-tn-1,a/2 or reject Ho if >tn-10 reject not reject x - Ho s/√n State the conclusion of this test. > In-1,α/2 Determine the value(s) for -tn-1,a, tn-1,a, or ±tn-1,0/2 as appropriate for this test. (Round to two decimal places as needed.) the null hypothesis. There (Round to two decimal places as needed. Use a comma to separate answers as needed.) Calculate the decision statistic. OB. Ho: 24 H₁: μ<4 O D. Ho: H=4 H₁: =4.08 is is not sufficient evidence that the population mean is greater than 4. ▸
Transcribed Image Text:A random sample of 171 marketing students was asked to rate, on a scale from 1 (not important) to 5 (extremely important), health benefits as a job characteristic. The sample mean rating was 4.08, and the sample standard deviation was 0.5. Test at the 10% significance level the null hypothesis that the population mean rating is at most 4 against the alternative that it is larger than 4. Click the icon to view the upper critical values of the Student's t distribution. What are the null and alternative hypotheses for this test? OA. H₂: H=4 H₁: μ#4 OC. Ho: ≤4 H₁: μ>4 O A. Reject H₂ if OB. Reject Ho if OC. Reject H if For this test at the significance level x with sample mean x, hypothesized mean μo, sample standard deviations, and sample size n, what is the form of the decision rule? x-Ho s/√n x-Ho s/√√n x - Ho s/√√n X-Ho s/√n <-tn-la <-tn-1,a/2 or reject Ho if >tn-10 reject not reject x - Ho s/√n State the conclusion of this test. > In-1,α/2 Determine the value(s) for -tn-1,a, tn-1,a, or ±tn-1,0/2 as appropriate for this test. (Round to two decimal places as needed.) the null hypothesis. There (Round to two decimal places as needed. Use a comma to separate answers as needed.) Calculate the decision statistic. OB. Ho: 24 H₁: μ<4 O D. Ho: H=4 H₁: =4.08 is is not sufficient evidence that the population mean is greater than 4. ▸
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