expression of the displacement is given by x(t) = 0.2cos(10t + ). At time t 0, %3D
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Q: Given the two displacements → = (6x+3y) m %3D → = ( 4x-5y)m Find the magnitude of 2→ -- А В
A: Given, the displacements: A→ = 6x^ + 3y^ mB→ = 4x^ - 5y^ m To find 2A→ - B→
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