Express the integral in terms of the variable u, but do not evaluate it. In x -dx; u = Inx e3 rel4 In x dx = du

Q: t² - Vi + Vi csc(t) dt

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Q: 4x V1- x³ dx

A: We will evaluate the given integral.

Q: S 6x®cos (x³) dx „8, ,3•

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Q: dx 4. xv9+4x2

A: Method:- I  use Trigonometry substitution method to solve the given integral

Q: Evaluate the Integral 2. S V5 + 12x – 9x²dx - ANSWER: 2. (3x-2)v5+12x-9x²+9Sin¬13*- 2]+C (3х-2)

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Q: 2x 35. x2 + 6x + 13 -бх + 13

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Q: Complete the trig substitution to achieve an integral involving trig functions of 0. Stop here; do…

A: Given: The integral is  ∫x2-4dx

Q: dx L2 exp %|

A: Given integral is I=∫-∞∞e-x2L2dx This type of integral cannot be done using elementary integration…

Q: Evaluate dx 2 1-x

A: We have to evaluate ∫23x1-xdx. We know that ∫dxx2-a2 = 12aln x-ax+a+C

Q: Use Table shown to rewrite as the difference of two integrals.

A: Given integral, ∫162x3-4xdx          ...(1)

Q: 3. Evaluate 5 sin rdr

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Q: -x Jez е sin x dx

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Q: dr Vr - 9

A: Given: I=∫drr3-9   ...1   As we know that; The Power rule: ∫xndx=xn+1n+1+C And ∫1ax+bdx=1alnax+b+C

Q: – dx x Inx x²+1

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Q: Integrate x² √6 +25 1 dx + C

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Q: Evaluate I = / a*. g³ Vx² – 3 dx

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Q: Compute 3+r+1 dx x2

A: Given : ∫233x2+2x+1x2dx

Q: . Evaluate the following integrals. 131 12-22--y // |v(x + 2)dzdydzr dzdydz -12 0

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Q: 21.3 xdx V16 - 9х4 0.

A: We to integrate the given integration.

Q: Evaluate the integral. Answer= +C -22e-30 e2x + 6e +5 12276 -da

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