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Express the improper integral as appropriate limits. foxe -x² dx Xe b ° - [/--) (- - -) lim -x2 xe dx + lim xe dx a-0 a b-00 lim (L x ²4x) + lim (1 * x -+²de) -x2 xe dx -x2 xe dx 9118 a b→∞ -~-~4) xe dx + lim b→∞ lim lim ax 0 lim a (SP) a - dx ---- xe b→∞ a -x2 dx -x2 xe dx

Express the improper integral as appropriate limits. foxe -x² dx Xe b ° - [/--) (- - -) lim -x2 xe dx + lim xe dx a-0 a b-00 lim (L x ²4x) + lim (1 * x -+²de) -x2 xe dx -x2 xe dx 9118 a b→∞ -~-~4) xe dx + lim b→∞ lim lim ax 0 lim a (SP) a - dx ---- xe b→∞ a -x2 dx -x2 xe dx

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Express the improper integral as appropriate limits. -X Late xe dx -8 0 I--) (S -x2 xe dx + lim b01 0 (Sve -j.2 xe dx + lim a b→ ∞ lim a-0 lim a→-∞ lim a →∞ lim a →∞ a 0 a b (S". a -x2 xe xe dx + lim b→ ∞ dx b JA) lim -x2 xe b→ ∞ a 0 dx -x2 xe dx 0 b - 0 xe b xe -x2 dx -x2 dx
Transcribed Image Text:Express the improper integral as appropriate limits. -X Late xe dx -8 0 I--) (S -x2 xe dx + lim b01 0 (Sve -j.2 xe dx + lim a b→ ∞ lim a-0 lim a→-∞ lim a →∞ lim a →∞ a 0 a b (S". a -x2 xe xe dx + lim b→ ∞ dx b JA) lim -x2 xe b→ ∞ a 0 dx -x2 xe dx 0 b - 0 xe b xe -x2 dx -x2 dx
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Step 1: Define the problem

The given integral is integral subscript negative infinity end subscript superscript infinity x e to the power of negative x squared end exponent d x

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