Express the confidence interval (747.7, 935.7) in the form of a + ME. + ME = 土
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![**Question 19**
**Express the confidence interval (747.7, 935.7) in the form of \( \bar{x} \pm ME \).**
\( \bar{x} \pm ME = \) [ ] \( \pm \) [ ]
---
**Explanation:**
This question requires you to express a given confidence interval as a mean (\( \bar{x} \)) plus or minus the margin of error (ME). The interval provided is from 747.7 to 935.7.
1. **Calculate the Mean (\( \bar{x} \)):**
\[
\bar{x} = \frac{747.7 + 935.7}{2} = 841.7
\]
2. **Calculate the Margin of Error (ME):**
\[
ME = \frac{935.7 - 747.7}{2} = 94
\]
Thus, the confidence interval in the form \( \bar{x} \pm ME \) is:
\[
841.7 \pm 94
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Transcribed Image Text:**Question 19**
**Express the confidence interval (747.7, 935.7) in the form of \( \bar{x} \pm ME \).**
\( \bar{x} \pm ME = \) [ ] \( \pm \) [ ]
---
**Explanation:**
This question requires you to express a given confidence interval as a mean (\( \bar{x} \)) plus or minus the margin of error (ME). The interval provided is from 747.7 to 935.7.
1. **Calculate the Mean (\( \bar{x} \)):**
\[
\bar{x} = \frac{747.7 + 935.7}{2} = 841.7
\]
2. **Calculate the Margin of Error (ME):**
\[
ME = \frac{935.7 - 747.7}{2} = 94
\]
Thus, the confidence interval in the form \( \bar{x} \pm ME \) is:
\[
841.7 \pm 94
\]
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