Express the confidence interval (45 %, 52.4 % ) in the form of p + ME.
Q: In a sample of 120 adults, 114 had children. Construct a 99% confidence interval for the true…
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Q: Express the confidence interval 14.4<p<28.4% in the form of p+-ME %+- %
A: Point estimate p-hat: The formula for point estimate is,
Q: In a sample of 350 adults, 277 had children. Construct a 99% confidence interval for the true…
A: The sample size, i.e., the sampled number of adults, n=350.The sampled number of adults with…
Q: A random survey of 70 male sophomores showed 16 preferred off campus living and out of 63 female…
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Q: Express the confidence interval (30.6 % , 43.6 % ) in the form of p ± ME. % + %
A: Express the confidence interval (30.6% , 43.6%) in the form of p^±ME.
Q: In a sample of 270 adults, 151 had children. Construct a 90% confidence interval for the true…
A: Given that Sample size n =270 Favorable cases x =151 Sample proportion p^=x/n =151/270 =0.5593
Q: A survey of 425 randomly selected students at one university found that 300 students think they…
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Q: Express the confidence interval (55.6%,69.6%) in the form of ˆp±ME then express it in trilnear…
A: It is given that , The confidence interval =(55.6%,69.6%) Aim: To obtain the confidence interval in…
Q: Express the confidence interval (50.6 %, 56.6 %) in the form of p + E. % +
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Q: Out of 600 people sampled, 486 had kids. Based on this, construct a 95% confidence interval for the…
A: It is given that Favourable cases, X = 486 Sample size, n = 600
Q: A new fertilizer was applied to the soil of 276 bean plants. 24% showed increased growth. Find the…
A: Given Data: p=0.24 n=276 z-value corresponding to 95% Confidence level=1.96
Q: In a survey, 22% of 230 single women said that they "definitely want to have children."In the…
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Q: A recent study of 2700 children randomly selected found 21% of them deficient in vitamin D. …
A: Given that, 2700 children randomly selected found 21% of them deficient in vitamin D. n=2700p^=0.21…
Q: If n = 160 and p (p-hat) = 0.85, construct a 95% confidence interval. Give your answers to three…
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Q: If n = 320 and p (p-hat) = 0.7, construct a 90% confidence interval. Give your answers to three…
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Q: In a sample of 290 adults, 191 had children. Construct a 95% confidence interval for the true…
A: 0.604 < p < 0.713 Explanation:Approach to solving the question:To construct a 95% confidence…
Q: Express the confidence interval (74.6%,82.4%)in the form of ˆp±ME
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Q: In a sample of 270 adults, 173 had children. Construct a 99% confidence interval for the true…
A: The sample size n= 270. The sample proportion is 173/270. The absolute value of Zα/2 is 2.5758 using…
Q: The confidence interval was (22, 26) What was the point estimate? What was the margin of error?
A: Given confidence interval was (22, 26)
Q: In a sample of 290 adults, 261 had children. Construct a 95% confidence interval for the true…
A: Given : Sample Size, n = 290 Number of successes, x = 261
Q: In a sample of 550 adults, 512 had children. Construct a 99% confidence interval for the true…
A: Given X=512 n=550
Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…
A: Given information
Q: In a sample of 350 adults, 277 had children. Construct a 99% confidence interval for the true…
A: Sample size, Number of adults having children, Confidence level is .
Q: press the confidence interval (81.8%,96.4%)(81.8%,96.4%) in the form of ˆp±E.
A: Given: Lower limit = 81.8% = 0.818 Upper limit = 96.4% = 0.964 The point estimate can be calculated…
Q: An internet service provider sampled 1000 of its customers, 189 of them experienced an interruption…
A: It is given that sample size (n) is 1000 and x is 189.
Q: As the sample standard deviation increases when all other parts of the confidence interval stay the…
A: We want tell the sample standard deviation increases when all other parts of the confidence interval…
Q: Express the confidence interval (75.7 % , 86.5 % ) in the form of p + E. %土
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Q: Suppose that a garage finds that 42 customers of 142 customers samples get their oil changes on…
A: The objective of this question is to find the lower bound of the 98% confidence interval for the…
Q: A motorcycle dealer with the "Hd" brand wants to know the percentage of students in the city "X" who…
A: We have to find confidence interval.
Q: Express the confidence interval ( 26.2%, 35.2%) in the form of p-hat plus or minus M.E.
A: Given Conference interval = (26.2℅ , 35.2℅) =(0.262 , 0.352)
Q: A firm randomly samples 100 workers at its New York plant and finds that 32% of the workers say that…
A: The proportion of workers who say that they buy the firm’s product is 0.32.
Q: Suppose that a garage finds that 42 customers of 142 customers samples get their oil changes on…
A: The objective of this question is to find the lower bound of the 98% confidence interval for the…
Q: In a sample of 300 adults, 267 had children. Construct a 90% confidence interval for the true…
A: To construct a 90% confidence interval for the population proportion, we'll use the formula for the…
Q: Suppose that a garage finds that 30 customers of 138 customers samples get their oil changes on…
A: The objective of this question is to find the upper bound of the 98% confidence interval for the…
Q: A recent study by the McGraw-Hill company showed that 61% (1621) of college students use their…
A: Given, Proportion of college students use their smartphones for study = 0.61Total number of students…
Q: During a period of 11 years, of 1700 people that were selected for grand jury duty, 30% of them were…
A: For large sample size population proportion will follow normal dustribution as per central limit…
Q: The mileage a car got on 5 trips from Greenwood to Greenville was used to create a 90% confidence…
A: Solution Given that 90% confidence interval is (32.32, 38.32).
Q: In a sample of 470 adults, 306 had children. Construct a 99% confidence interval for the true…
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- In a sample of 460 adults, 281 had children. Construct a 90% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places < p <A random sample of 120 rhesus monkeys found that the number of rhesus monkeys that live in a captive breeding facility is 77. Construct a 90% confidence interval for the true proportion of rhesus monkeys that live in a captive breeding facility.2
- Suppose that a garage finds that 30 customers of 138 customers samples get their oil changes on time. Find a 98% confidence interval of the true proportion. What is the upper bound of the confidence interval? (round to 4 decimal places)During the 2016 season, Lauren Robinson had 92 at bats and made 36 hits. Calculate a 95% confidence interval for her ABILITY to get hits in that season.In a sample of 360 adults, 266 had children. Construct a 95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three placesRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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