Express the confidence interval 37.3 % < p < 54.7 % 37.3 % < p < 54.7 % in the form of ˆ p ± E p ^ ± E . % ± ± %
Q: Express the confidence interval 8.5%<p<25.3% in the form of p±ME.
A: Solution: From the given information, the confidence interval for the population proportion is…
Q: Express the confidence interval 57.7%±9%57.7%±9% in interval form.
A: Given Information: Confidence interval = (57.7% ± 9%)
Q: Express the confidence interval (35.2%,48.4%)(35.2%,48.4%) in the form of ˆp±Ep^±E. % ±…
A:
Q: Express the confidence interval (45.3%,59.3%)(45.3%,59.3%) in the form of ˆp±MEp^±ME. % ± %
A: The margin of error is, Thus, the margin of error is 0.07.
Q: Express the confidence interval 61.5%<p<78.1%61.5%<p<78.1% in the form of ˆp±MEp^±ME.
A:
Q: Express the confidence interval (55.6%,69.8%)(55.6%,69.8%) in the form of ˆp±MEp^±ME. ___% ± ___%
A:
Q: Express the confidence interval 27.1%±8.5%27.1%±8.5% in interval form.
A: The given confidence interval is 27.1%±8.5%.
Q: Express the confidence interval 81.9%. ±. 4.6%. in interval form.
A: Confidence interval is the estimate of the interval of an unknown population parameter. It provides…
Q: Express the confidence interval 30.7 % <p< 43.5 % in the form of p + E.
A:
Q: Express the confidence interval (19.1%,34.5%)(19.1%,34.5%) in the form of ˆp±Ep^±E. . % ± .…
A: The confidence is in the form: (Lower limit, Upper limit) Hence, Plug in all the values in the…
Q: Express the confidence interval ( 66.9 % , 73.3 % ) ( 66.9 % , 73.3 % ) in the form of ˆ p ± E p ^ ±…
A: Solution-: Given: The C.I. is (66.9%, 73.3%) We express given C.I. in the form of p^±E
Q: Express the confidence interval 44.1%±7.6%44.1%±7.6% in interval form.
A:
Q: Express the confidence interval 71.4%±4.3% in interval form.
A: Express the confidence interval 71.4%±4.3% in interval form.
Q: xpress the confidence interval (34%,47.2%)(34%,47.2%) in the form of ˆp±MEp^±ME. % ±± %
A: Given data, Confidence interval is (34%,47.2%) Lower limit=34 Upper limit=47.2 Express in form…
Q: Express the confidence interval (14.1 %, 20.1 %) in the form of p + ME. % ± R
A: Given confidence interval is(14.1%,20.1%)Upper limit=20.1%Lower limit=14.1%
Q: Express the confidence interval 74.1%±4.2%74.1%±4.2% in interval form
A: Express the confidence interval 74.1%±4.2%74.1%±4.2% in interval form
Q: Express the confidence interval 27.3%±8.3%27.3%±8.3% in interval form.
A: Given that, Confidence Interval = 27.3% ± 8.3%
Q: press the confidence interval 11.1%<p<24.9%11.1%<p<24.9% in the form of ˆp±MEp^±ME
A: given data, the confidence interval is 11.1%<p<24.9%we can also write without percentage…
Q: Express the confidence interval 33%<p<46%33%<p<46% in the form of ˆp±MEp^±ME. % ± %
A:
Q: Express the confidence interval 71.5%±6.9%71.5%±6.9% in interval form.
A: Confidence Interval: Confidence interval is the interval estimate of the population parameter. It is…
Q: Express the confidence interval (47%,53.8%)(47%,53.8%) in the form of ˆp±Ep^±E. % ±± %
A:
Q: Express the confidence interval 36.6%<p<43.8%36.6%<p<43.8% in the form of ˆp±Ep^±E.
A: From the given information, the confidence interval is 0.366 and 0.438The sample proportion value is…
Q: Express the confidence interval 5.4 % < p < 15.2 % in the form of p + E. %
A: Solution
Q: Express the confidence interval (27.4%,34.8%)(27.4%,34.8%) in the form of ˆp±Ep^±E. % ±± %
A: The random variable X follows binomial distribution. The given confidence interval shows one…
Q: Express the confidence interval
A: The point estimate (p^) can be calculated as:p^ = (LowerLimit + UpperLimit)\(2) p^ =(0.651+0.805)/2…
Q: Express the confidence interval 41.9%<p<49.9%41.9%<p<49.9% in the form of ˆp±Ep^±E.
A: The given confidence is interval is, 41.9%<p<49.9% The upper limit p^+E=49.9%The lower limit…
Q: Express the confidence interval 49.8%<p<67.6%49.8%<p<67.6% in the form of ˆp±Ep^±E.
A: Here we need to express the given confidence interval in the form p+/-E.
Q: ress the confidence interval (30%,43.2%)(30%,43.2%) in the form of ˆp±MEp^±ME. ___% ± ___%
A: Given Confidence interval is (30%,43.2%)Lower limit=30%Upper limit=43.2%Express in form of p±E
Q: Express the confidence interval 5.6 % < p < 14.4 % in the form of p ± E.
A: We need to use the concept of Confidence intervals
Q: Express the confidence interval 10.8%±5.1%10.8%±5.1% in interval form.
A: The given expression is 10.8% ± 5.1%.
Q: form
A: The confidence interval for p is 33.4%<p<43.6% From the given information, p̂ - E = 33.4% p̂…
Q: Express the confidence interval 43.8 % < p < 53.4 % in the form of p± E. %
A:
Q: Express the confidence interval 62.3%<p<78.3%62.3%<p<78.3% in the form of ˆp±Ep^±E. % ±± %
A:
Q: Express the confidence interval 85.9%<p<91.9%85.9%<p<91.9% in the form of ˆp±Ep^±E. % ± %
A: Point estimate ± Margin of error = (85.9, 91.9) Sample proportion +Margin of error = 91.9 Sample…
Q: Express the confidence interval (76.5 % , 87.1 % ) in the form of p ± ME. % +
A: The given confidence interval is, (76.5%,87.1%) The formula of confidence interval is, The sample…
Q: Express the confidence interval 69.7 % < p < 86.5 % in the form of p ± E.
A: Given. 69.7% <p<86.5%
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- Express the confidence interval (6.6%,15.4%)(6.6%,15.4%) in the form of ˆp±Ep^±E._____ % ± _____ %Express the confidence interval (832.7,935.9)(832.7,935.9) in the form of ¯x±MEx¯±ME.¯x±ME=__________±___________Express the confidence interval 62.3%<p<78.3%62.3%<p<78.3% in the form of ˆp±Ep^±E.% ±± %
- In the regression equation, ŷ = 2.164 + 1.3657x, and n = 6, the mean of x is 8.667, SSxx= 89.333 and Se= 3.44. A 95% confidence interval for the average of y when x=8 is ______. a) (9.13, 17.05) b) (2.75, 23.43) c) (10.31, 15.86) d) (3.56, 22.62) e) (12.09, 14.09)Express the confidence interval 36.6%<p<54.6%36.6%<p<54.6% in the form of ˆp±MEp^±ME.% ±± %Express the confidence interval 0.111<p<0.333 in the form p±E. p±E=_____±____
- A regression was run to determine if there is a relationship between hours of study per week (xx) and the final exam scores (yy).The results of the regression were: y=ax+b a=6.22 b=21.6 r2=0.477481 r=0.691 Use this to predict the final exam score of a student who studies 8 hours per week, and please round your answer to a whole number.You conducted a regression analysis between the number of absences and number of tasks missed by your 5 classmates in Statistics and Probability. It resulted that the regression line is y = 0.65x + 1.18. What is the predicted number of tasks missed of a learner who is always present? O a. The learner has 1 task missed. O b. The learner has less than 2 tasks missed. O c. The learner has more than 2 tasks missed. o d. The learner has no task missed.A regression was run to determine if there is a relationship between hours of study per week (xx) and the test scores (yy).The results of the regression were:y=ax+b a=5.89 b=34.42 r2=0.837225 r=0.915 Use this to predict the final exam score of a student who studies 6 hours per week, and please round your answer to a whole number.
- 10) A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y).The results of the regression were:y=ax+b a=-0.767 b=31.009 r2=0.609961 r=-0.781 Use this to predict the number of situps a person who watches 7.5 hours of TV can do (to one decimal place)A positive correlation coefficient means that there is a relationship between two variables. O Zero Direct O Inverse O ProportionalConsider the following data on price ($) and the overall score for six stereo headphones tested by a certain magazine. The overall score is based on sound quality and effectiveness of ambient noise reduction. Scores range from 0 (lowest) to 100 (highest). Brand Price ($) Score A 180 74 B 150 69 95 59 70 56 70 42 F 35 24 (a) The estimated regression equation for this data is ý = 23.398 + 0.306x, where x = price ($) and y = overall score. Does the t test indicate a significant relationship between price and the overall score? Use a = 0.05. State the null and alternative hypotheses. O Ho: Bo = 0 H: Bo + 0 O Ho: B, = 0 O Ho: B1 + 0 H: B1 = 0 O Ho: B, 20 H: B, < 0 O Ho: Bo *0 H: Bo = 0 Find the value of the test statistic. (Round your answer to three decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = What is your conclusion? O Do not reject Hn. We cannot conclude that the relationship between price ($) and overall score is significant. O Reject H.. We…
