Express the confidence interval 0.039
Q: Express the confidence interval 43.1 % <p < 59.3 % in the form of p+ ME. Question Help: Post to…
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Q: Many people believe that the average number of Facebook friends is 135. The population standard…
A: (A) State the hypotheses. Determine the type of the test used. The type of the test used is…
Q: Give a 99.5% confidence interval, for μ1−μ2μ1-μ2 given the following information. n1=25, ¯x1=2.4 ,…
A: There are two independent samples which follows normal distribution. We have to construct 99.5%…
Q: Express the confidence interval (28.1,203.3)(28.1,203.3) in the form of ¯x±MEx¯±ME. ¯x±ME=x¯±ME=…
A: Express the confidence interval (28.1,203.3) in the form of ¯x±ME
Q: A 99% confidence interval estimate of the standard deviation of body temperature of all healthy…
A: Given sample size,n = 109 df=n-1= 108 sample standard deviation,s= 0.64…
Q: Construct the indicated confidence interval for the population mean muμ using the t-distribution.…
A: The given values are:Confidence level (c) = 0.90Sample mean (x̄) = 14.5Sample standard deviation (s)…
Q: A simple random sample of size n= 40 is drawn from a population. The sample mean is found to be x =…
A: According to the given information, we have X¯=121.7s=12.3n=4099% confidence level
Q: Express the confidence interval 308.6±77.5308.6±77.5 in the form of a trilinear inequalit
A: confidence interval for population mean : 308.6±77.5 we have to represent it in trilinear…
Q: A simple random sample of size nequals=40 is drawn from a population. The sample mean is found to be…
A: It is given that:
Q: An electrical firm manufactures light bulbs that have a length life with normal distribution, and a…
A: To find the 95% confidence interval for the average length life, we'll use the formula for a…
Q: What is the formula for the confidence interval for u with o unknown? O A. xit-a/2; n-1 S. O B. x+Z1…
A: A confidence interval(CI) shows the probability that a constraint will lie between a pair of values…
Q: K Express the confidence interval 0.555 <p<0.999 in the form p±E. P±E=±
A: the confidence interval is : 0.555<p<0.999 express this confidence interval in the form of…
Q: Express the confidence interval 0.49±0.0470.49±0.047 in open interval form (i.e., (0.155,0.855)).
A: We have to convert ci in given form.
Q: 343.5±65.3343.5±65.3 in the form of a trilinear inequality
A: The confidence interval is given as, The trilinear equation is of the form
Q: On the basis of a random sample of 100 men from a particular province in USA, a 95% confidence…
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Q: Express the confidence interval 245.3±132.9245.3±132.9 in the form of a trilinear inequality. That…
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Q: A 95% confidence interval for μ is computed to be (2.15, 2.75). For each of the following…
A: We have given that, A 95% confidence interval for μ is computed to be ( 2.15 , 2.75 ) . The null…
Q: Express the confidence interval (175.3,290.3)(175.3,290.3) in the form of ¯x±MEx¯±ME. ¯x±ME=x¯±ME=…
A: Express the confidence interval (175.3,290.3) in the form of ¯x±ME
Q: The proportion of on-line shoppers who actually make a purchase appears to be relatively constant…
A: The random variable purchased merchandise follows binomial distribution. There are two samples which…
Q: The null hypotheses should be rejected for p-value = 0.0153 and a 0.01 %3D
A: Given : p-value=0.0153 , α=0.01 The decision rule by using p-value is given by, Reject Ho if…
Q: A car salesperson claims that the mean gas mileage for its luxury sedan is at least 32 miles per…
A: t-test: If the given sample size is less than or equal to 30 then that is a small sample test.…
Q: Express the confidence interval 351 < µ < 525.4 in the form of x + ME. x + ME= H
A:
Q: Only 11% of registered voters voted in the last election. Will voter participation change for the…
A: From the provided information, Population proportion (p) = 0.11 Sample size (n) = 380 Out of which…
Q: Give a 99% confidence interval, for μ₁ −μ₂ given the following information. n₁ = 60, x1 = 2.53, $1…
A: Given 99% confidence interval, n1 = 60, x1=2.53 n2 = 50, X2=2.95 S1=0.78,S2=0.94
Q: Express the confidence interval 0.2222<p<0.6666 in the form p±E.
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Q: is there enough evidence to support the administrator's claim
A: Given that Sample size(n)= 76 Sample mean (x¯) = 283 Population standard deviation(σ) = 31 Level of…
Q: Express the confidence interval 361.4<μ<603.4361.4<μ<603.4 in the form of x¯±ME.…
A:
Q: In order to conduct a hypothesis test of the population mean, a random sample of 30 observations is…
A: State the hypotheses.
Q: In order to conduct a hypothesis test of the population mean, a random sample of 20 observations is…
A: Solution: State the hypotheses. Null hypothesis: H0: µ≤11.3 Alternative hypothesis: HA: µ>11.3…
Q: If my result is significant, do I reject my null hypothesis?: The t-value is 2.76273. The p-value…
A: a) From the given information, t-value = 2.76273 p-value = 0.006739 The significance level = 0.05…
Q: Express the confidence interval 119.5<μ<335.1119.5<μ<335.1 in the form of ¯x±MEx¯±ME.
A: The given confidence interval is, 119.5<μ<335.1 The value of sample mean is,
Q: Give a 98% confidence interval, for μ1−μ2μ1-μ2 given the following information. n1=50n1=50,…
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Q: Express the confidence interval (568.6,779.6) in the form of ¯x±ME. ¯x ± ME = ±
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Q: Express the confidence interval 57.2 % < p < 71.4 % in the form of p + E. % +
A: From the provided information Confidence interval 57.2% < p < 71.4%
Q: Express the confidence interval −47.5<μ<173.3-47.5<μ<173.3 in the form of ¯x±MEx¯±ME. ¯x±ME=x¯±ME=…
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Q: Researchers collected two different samples, X and Y, of temperatures, in degrees Celsius, of the…
A: Introduction: Confidence interval is the interval estimate of the population parameter. It is the…
Q: Express the confidence interval (504.1,571.5)(504.1,571.5) in the form of ¯x±MEx¯±ME. ¯x±ME=…
A:
Q: A random sample of 10 observations are selected from a normal population. Let X be the sample mean…
A: Given information: The confidence level is 95%.
Q: The life expectancy of a male during the course of he past 100 years is approximately 27,715 days.…
A: Population mean μ =27715
Q: Express the confidence interval with ¯xx¯ = 415.2 and ME = 96.5 by stating the lower and upper…
A: The lower bound of the confidence interval is given by The upper bound of the confidence interval…
Q: Express the confidence interval 309.4±61309.4±61 in the form of a trilinear inequality.
A: Dear student as per guidelines we answer the first question only when multiple different questions…
Q: Express the confidence interval 0.111 < p < 0.333 in the form p± E. p±E = ± ☐
A: Let, p = sample proportion and E = Margin of Error Then,Lower Limit = p−E=0.111 eqt. 1Upper…
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- A simple random sample of size n = 40 is drawn from a population. The sample mean is found to be 103.7, and the sample standard deviation is found to be 20.4. Is the population mean greater than 100 at the x = 0.10 level of significance? Determine the null and alternative hypotheses. Ho: H₁: Compute the test statistic. = (Round to two decimal places as needed.) Determine the P-value. The P-value is . (Round to three decimal places as needed.) What is the result of the hypothesis test? the null hypothesis because the P-value is the level of significance. At the α = 0.10 level of significance, the population meanA carpet company advertises that it will deliver your carpet within 16 days of purchase. A sample of 49 past customers is taken. The average delivery time in the sample was 17.1 days. The standard deviation of the population (?) is known to be 5.6 days. (a) State the null and alternative hypotheses (in days) for a test to determine if their advertisement is legitimate. (Enter != for ≠ as needed.) H0: Ha: (b) Using the critical value approach, test the hypotheses. Let ? = 0.05. Compute the test statistic. (Round your answer to two decimal places.) Determine the critical value(s) for this test. (Round your answer(s) to two decimal places. If the test is one-tailed, enter NONE for the unused tail.) test statistic≤test statistic≥ State your conclusion. Reject H0. There is sufficient evidence to conclude that their advertisement is not legitimate.Do not reject H0. There is insufficient evidence to conclude that their advertisement is not legitimate. Do not…From the Gaussian error curve, what is the probability that a result From population lies between +o and +20 ? Given that area under Gaussian curve for + o= 68.3% and + 20=95.4% O 30.65 % 20.22 % 13.6% O34.2% O47.7 %
- Express the confidence interval −15.5<μ<99.9-15.5<μ<99.9 in the form of ¯x±MEx¯±ME.Express the confidence interval 23.5±101.123.5±101.1 in the form of a trilinear inequality. <μ<Give a 98% confidence interval, for μ1−μ2 given the following information. n1=45 xbar1=2.62, s1=0.8n2=60n xbar = 3.02, s2=0.67 ____ ±± ____ Use Technology Rounded to 2 decimal places.
- Give a 90% confidence interval, for μ1−μ2μ1-μ2 given the following information. n1=20, x¯1=2.95, s1=0.7n2=30, ¯x2=2.76 , s2=0.75 __±___ Use Technology Rounded to 2 decimal places.Express the confidence interval 338.2<μ<536.8 in the form of x±MEx±ME= ±Only 19% of registered voters voted in the last election. Will voter participation increase for the upcoming election? Of the 339 randomly selected registered voters surveyed, 75 of them will vote in the upcoming election. What can be concluded at the αα = 0.05 level of significance? The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer reject accept fail to reject the null hypothesis. Thus, the final conclusion is that ... A) The data suggest the population proportion is not significantly higher than 19% at αα = 0.05, so there is statistically insignificant evidence to conclude that the percentage of registered voters who will vote in the upcoming election will be higher than 19%. B) The data suggest the population proportion is not significantly higher than 19% at αα = 0.05, so there is statistically significant evidence to conclude that the percentage of registered voters who will vote in the…
- To construct a confidence interval for the difference between two population means μ₁ −μ2, use the form 0²2 0²/ 0²/2 + (x₁-x₂) -ZcA Express the confidence interval 0.444 < p <0.888 in the form p±E. p±E= +C H7.1.9 Express the confidence interval 0.777SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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