Express in four decimal places. Express the quantity in the unit indicated and designate whether this heat is gained or lost by the substance(12 pts) a. The quantity of heat in calories when 162.5 grams of water undergoes a temperature decrease from 45.84 oC to 40.00oC. b. The quantity of heat in Kilojoules when 43.5 Kg of chloroform ,CHCl3 has its temperature changed from 16.8oC to 22.3oC ( sp ht of CHCl3 = 0.971 KJ/kg-o

Q: A 6.57 g sample of an unknown salt (MM = 116.82 g/mol) is dissolved in 150.00 g water in a coffee…

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Q: A student wishes to determine the heat capacity of a coffee-cup calorimeter. After mixing 125 g of…

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Q: A 7.37 g sample of an unknown salt (MM = 116.82 g/mol) is dissolved in 150.00 g water in a coffee…

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Q: A 4.79 g sample of an unknown salt (MM = 116.82 g/mol) is dissolved in 150.00 g water in a coffee…

A: Calorimetry is the easiest way to calculate the amount of heat transfer to a substance or from a…

Q: 3. When 2.0 g of NaOH is the heat of dissolution are dissolved in 49.0 g of water, the temperature…

A: 3.) First we need to calculate the heat using the formula Q = mC∆T  Then we need to calculate moles…

Q: 4.33g sample of an unknown salt (MM=116.83g/mol) is dissolved in 150.00g water coffee cup…

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Q: A 7.03 g sample of an unknown salt (MM = 116.82 g/mol) is dissolved in 150.00 g water in a coffee…

A: We know during the process of any reaction, heat gained  = heat lost . For above the formula used…

Q: The specific heat of a substance is the amount of heat required to raise the temperature of one gram…

A: Given --> Q = 357 J  S = 0.362 J/g°C T1 = 24.1°C T2 = 80.6°C

Q: If 63.50 g of an unknown metal at 97.6 °C initially produced a resulting temperature of 39.5 °C when…

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: The table lists the specific heat values of several substances. Substance Specific heat (cal/g.°C)…

A: Heat energy is given by q = m * C * ΔT where q = heat energy m = mass of the substance C = specific…

Q: The change in enthalpy (heat of solution) for ammonium nitrate dissolving in water is 25.7 kJ/mol.…

A: Given,  The change in enthalpy (heat of solution) for ammonium nitrate dissolving in water is 25.7…

Q: The change in enthalpy (heat of solution) for ammonium nitrate dissolving in water is 25.7 kJ/mol.…

A: Molar mass of ammonium nitrate =80.043g/mol

Q: 4. How much will the temperature of a cup (180 g) of coffee at 95 °C be reduced when a spoon…

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Q: A substance weighing 14.2 g absorbs 65.03 J of heat, resulting in a temperature increase of 10.2 °C.…

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A: Mass of substance = m = 16.3 g Temperature increased by Means change in temperature = ∆T = 12.5°c…

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Q: 3. a. What is the specific heat of a 41.5 g piece of glass, if it takes 17.8 kJ of heat to raise its…

A: (3a) Specific heat of a Substance can be calculated by using Following formula - Q = C M ∆T Here, Q…

Q: 100 g of a solution (specific heat of 0.32 J/g C) undergoes a reaction in which 74.84 J of heat is…

A: Mass of solution = 100 g Specific heat = 0.32 J/g oC Heat released = 74.84 J

Q: A chunk of metal having a mass of 49.7g was warmed to 95.5°C and then dropped into a calorimeter…

A: Mass of metal = 49.7g  Mass of water = 45.3g Heat capacity for water = 4.18J/g°C Final temperature =…

Q: Calculate the heat change (q) in J when 8.111 grams of water is cooled from 1.472 ºC to -2.592 ºC.

A: The heat change during a temperature change ca be calculated as follows. q=mc∆Tq=heat…

Q: A 4.35 g sample of an unknown salt (MM = 116.82 g/mol) is dissolved in 150.00 g water in a coffee…

A: The heat released or absorbed (q) when the temperature of any substance is raised is calculated as:…

Q: A 8.17 g sample of an unknown salt (MM = 116.82 g/mol) is dissolved in 150.00 g water in a coffee…

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Q: A sample of gold weighing 7.7 grams is cooled then placed in a calorimeter containing 27.01 grams of…

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Q: IN B C. LI %#3 Assume that it is possible to heat water with perfect insulation (all the heat from…

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Q: A 4.81 g sample of an unknown salt (MM = 116.82 g/mol) is dissolved in 150.00 g water in a coffee…

A: Given, Mass of unknown sample ,ms=4.81 g  mass of water, mw= 150 g initial temperature Ti=23.72°C…

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Q: A solution is made by mixing 197.3 g of ethanol initially at 10.5°C with 250.0 g of water initially…

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Q: A 22.0 g sample of pure iron at 85 °C is dropped into 73 g of water at 20. °C. What is the final…

A: Mass of pure iron sample = 22.0 g Initial temperature of pure iron sample = 85o C  Mass of water =…

Q: 7. If it takes 105 joules to warm 100 grams of a substance from 20°C to 25°C, what is the specific…

A: Since you have asked multiple question, we will solve the first questionfor you. If you want any…

Q: A 6.55 g sample of an unknown salt (MM = 116.82 g/mol) is dissolved in 150.00 g water in a coffee…

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Q: If 4210 J of heat is added to a calorimeter containing 254 g of water, the temperature of the water…

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Q: A 6.57 g sample of an unknown salt (MM = 116.82 g/mol) is dissolved in 150.00 g water in a coffee…

A: “Since you have posted a question with multiple sub-parts, we will solve first three subparts for…

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Q: A 9.13-g sample of vanadium is heated to 99.10 °C and is then placed into 20.0 g water in a…

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Q: In the laboratory a "coffee cup" calorimeter, or constant pressure calorimeter, is frequently used…

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Q: 27-gram piece of metal at 144  oC is dropped into 86 grams of water at 29 oC.  The water temperature…

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Q: A student is asked to identify an unknown piece of metal. The metal has a mass of 12.34 g. It is…

A: Given data,Mass of metal=12.34gTemperature of metal (Tm)=99.98oCVolume of water=103.25mLDensity of…

Q: Calculate the heat change (q) in J when 4.297 grams of water is cooled from 3.967 ºC to -2.902 ºC.

A: Given: Mass of water, m=4.297 g  Initial temperature, T1= 3.967 ºC Final temperature, T2=-2.902 ºC…

Q: 3. A 74.5 g piece of metal at 86.0°C is placed in 133 g of water at 21.0°C contained in a…

A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…