exponent = math.exp(-(math.pow(x-mean,2)/(2*math.pow(stdev,2)))) return (1 / (math.sqrt(2*math.pi) * stdev)) * exponent use laplace smoothing to remove the zero division error. Want a code in python The below code won't work as later when I use it create zero division error So laplace smoothing has to be added to the formula def calculateProbability(x, mean, stdev): try: exponent = math.exp(-(math.pow(x - mean, 2) / (2 * math.pow(stdev, 2)))) except ZeroDivisionError: exponent = 0 #or whatever print (stdev,"||",exponent) print (2 * math.pow(stdev, 2)) return (1 / (math.sqrt(2 * math.pi) * stdev)) * exponent

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