Explain, with the aid of a diagram, and with reference to the concept of total internal reflection, how triangular prisms can be used instead of mirrors to build a periscope. Will the image be upright? Will it be laterally inverted
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Explain, with the aid of a diagram, and with reference to the concept of total internal reflection, how triangular prisms can be used instead of mirrors to build a periscope. Will the image be upright? Will it be laterally inverted?
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- A diverging lens (f=-12.0 cm) is located 22.0 cm to the left of a converging lens (f=34.0 cm). A 3.70 cm tall object stands to the left of the diverging lens, exactly at its focal point. (a) Determine the distance of the final image relative to the converging lens. (b) What is the height of the final image (including the proper algebraic sign)?A 3 cm tall object is placed 16 cm from a converging lens with a focal length of 12 cm. A diverging lens with a focal length of 10 cm is placed 36 cm behind the converging lens. Both lenses have the same principal axis. Draw the ray diagram to graphically find the final image. Need only handwritten solution only (not typed one).Consider a 2.5-cm tall candle positioned 7.5 cm in front of a concave spherical mirror with a radius of 30 cm. Determine and explain the characteristics of the resulting image. Please create a scaled ray diagram to aid in your explanation. Also, calculate the longitudinal magnification of the candle's image.
- A blue whale eyeball may be taken as a sphere that is about 15 cm in diameter. Assuming that it is filled with material with an index of refraction of 1.5, where would the image form for an object (in water) that is very far away? Just consider the initial image formed by refraction through the front surface. Select answer from the options below 15 cm behind the back of the eye 7.5 cm behind the front surface of the eye 15 cm behind the front surface of the eye Approximately 30 cm behind the back of the eye Approximately 50 cm behind the back of the eyeCurrent Attempt in Progress More lenses. Object O stands on the central axis of a thin symmetric lens. For this situation (see the table below, all distances are in centimeters), find (a) the lens type, converging or diverging, (b) the focal distance f, (c) the image distance i. It also refers to whether (d) the image is real or virtual, and (e) on the same side of the lens as O or on the opposite side. (a) (b) Number (c) Number i (d) w god (e) < (a) (b) Type fp Units Units +12 (c) i m 0.30 (d) (e) R/V I/NI Side NI <Please don't provide handwritten solution.... A diverging lens with f = -37.5 cm is placed 15.0 cm behind a converging lens with f = 21.0 cm .Where will an object at infinity be focused? Determine the image distance from the second lens. Follow the sign conventions.
- a) What is the apparent depth of an object that is 1.5 meters below the surface of water? (b) Sketch a rough ray diagram showing the object and image below the water's surface. c. When observing the convex side of a shiny spoon, which is approximately spherical with a radius of 5.0 cm, calculate the location of the your image be if you are 18 cm away from it? (d) Is this a real or virtual image? (e) Is your image right-side up or upside down? (e) How would your answers to the previous questions change if you were 18 cm away from the concave side of the spoon? ( Give specific numerical answers)To work this problem, use the fact that the image formed by the first surface becomes the object for the second surface. The figure below shows a piece of glass with index of refraction n = 1.50 surrounded by air. The ends are hemispheres with radii R₁ = 2.00 cm and R₂ = 4.00 cm, and the centers of the hemispherical ends are separated by a distance of d = 8.06 cm. A point object is in air, a distance of p = 1.06 cm from the left end of the glass. R₁ R₂ d (a) Locate the image of the object due to refraction at the two spherical surfaces. 1.222 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. cm to the right of the second surface (b) Is the image real or virtual? O real O virtual