Explain why S is not a basis for M22

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Question 6: Explain why S is not a basis for M2x2.**

**Given Set:**

\[ S = \left\{ \begin{bmatrix} 1 & 1 \\ 0 & 0 \end{bmatrix}, \begin{bmatrix} 0 & 1 \\ 0 & 0 \end{bmatrix} \right\} \]

**Explanation:**

To determine if the set \( S \) is a basis for \( M2x2 \), which is the space of 2x2 matrices, we need to check if \( S \) satisfies two conditions:

1. **Spans \( M2x2 \):** A basis must span the entire space of 2x2 matrices. This means any 2x2 matrix should be expressible as a linear combination of the matrices in \( S \).

2. **Linear Independence:** The matrices in \( S \) must be linearly independent, meaning no matrix in the set can be written as a linear combination of the others.

Since \( M2x2 \) is a 4-dimensional space (as it consists of 2x2 matrices, totaling 4 elements), a basis for this space must contain 4 linearly independent matrices. However, set \( S \) only contains 2 matrices.

Therefore, \( S \) cannot be a basis for \( M2x2 \) because it contains fewer matrices than the dimension of the space.
Transcribed Image Text:**Question 6: Explain why S is not a basis for M2x2.** **Given Set:** \[ S = \left\{ \begin{bmatrix} 1 & 1 \\ 0 & 0 \end{bmatrix}, \begin{bmatrix} 0 & 1 \\ 0 & 0 \end{bmatrix} \right\} \] **Explanation:** To determine if the set \( S \) is a basis for \( M2x2 \), which is the space of 2x2 matrices, we need to check if \( S \) satisfies two conditions: 1. **Spans \( M2x2 \):** A basis must span the entire space of 2x2 matrices. This means any 2x2 matrix should be expressible as a linear combination of the matrices in \( S \). 2. **Linear Independence:** The matrices in \( S \) must be linearly independent, meaning no matrix in the set can be written as a linear combination of the others. Since \( M2x2 \) is a 4-dimensional space (as it consists of 2x2 matrices, totaling 4 elements), a basis for this space must contain 4 linearly independent matrices. However, set \( S \) only contains 2 matrices. Therefore, \( S \) cannot be a basis for \( M2x2 \) because it contains fewer matrices than the dimension of the space.
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