Explain why each compound is aromatic, anti aromatic or non aromatic? Explain А. В. С. D.

Organic Chemistry: A Guided Inquiry
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ISBN:9780618974122
Author:Andrei Straumanis
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Chapter18: Aromaticity
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### Aromaticity of Compounds

**Objective:**
Explain why each compound is aromatic, antiaromatic, or non-aromatic.

**Compounds:**
- **A.**
- **B.**
- **C.**
- **D.**

**Detailed Description with Diagram Explanation:**

1. **Compound A:**
   - Structure: This compound consists of a six-membered ring (a hexagon) with alternating double bonds, known as benzene. 
   - **Diagram Analysis:** The structure indicates a planar, cyclic molecule with six π (pi) electrons, fitting Huckel's rule \(4n + 2 = 6\), where \(n = 1\).
   - **Conclusion:** This compound is aromatic.

2. **Compound B:**
   - Structure: This compound is similar to benzene but has a negative charge on one of the carbon atoms, making it a cyclohexadienyl anion.
   - **Diagram Analysis:** The negative charge contributes two additional π electrons, totaling eight π electrons. According to Huckel's rule, \(4n + 2 = 8\), where \(n\) would not be an integer.
   - **Conclusion:** This compound is antiaromatic because it does not satisfy Huckel's rule and has 4n π electrons (where \(n = 2\)).

3. **Compound C:**
   - Structure: This compound is a five-membered ring (a pentagon) with alternating double bonds and a positively charged carbon center, known as cyclopentadienyl cation.
   - **Diagram Analysis:** It has a total of four π electrons. According to Huckel's rule, \(4n + 2 = 4\), where \(n\) would be an integer (\(n = 1\)).
   - **Conclusion:** This compound is antiaromatic because it has 4 π electrons and is planar and cyclic.

4. **Compound D:**
   - Structure: This compound is a linear structure with alternating single and double bonds, covering six carbon atoms.
   - **Diagram Analysis:** The molecule is not cyclic, making it impossible to delocalize π electrons in a ring.
   - **Conclusion:** This compound is non-aromatic because it is not a cyclic structure and therefore does not meet the criteria for aromaticity or antiaromaticity.

By analyzing the structure and using Huckel's rule,
Transcribed Image Text:### Aromaticity of Compounds **Objective:** Explain why each compound is aromatic, antiaromatic, or non-aromatic. **Compounds:** - **A.** - **B.** - **C.** - **D.** **Detailed Description with Diagram Explanation:** 1. **Compound A:** - Structure: This compound consists of a six-membered ring (a hexagon) with alternating double bonds, known as benzene. - **Diagram Analysis:** The structure indicates a planar, cyclic molecule with six π (pi) electrons, fitting Huckel's rule \(4n + 2 = 6\), where \(n = 1\). - **Conclusion:** This compound is aromatic. 2. **Compound B:** - Structure: This compound is similar to benzene but has a negative charge on one of the carbon atoms, making it a cyclohexadienyl anion. - **Diagram Analysis:** The negative charge contributes two additional π electrons, totaling eight π electrons. According to Huckel's rule, \(4n + 2 = 8\), where \(n\) would not be an integer. - **Conclusion:** This compound is antiaromatic because it does not satisfy Huckel's rule and has 4n π electrons (where \(n = 2\)). 3. **Compound C:** - Structure: This compound is a five-membered ring (a pentagon) with alternating double bonds and a positively charged carbon center, known as cyclopentadienyl cation. - **Diagram Analysis:** It has a total of four π electrons. According to Huckel's rule, \(4n + 2 = 4\), where \(n\) would be an integer (\(n = 1\)). - **Conclusion:** This compound is antiaromatic because it has 4 π electrons and is planar and cyclic. 4. **Compound D:** - Structure: This compound is a linear structure with alternating single and double bonds, covering six carbon atoms. - **Diagram Analysis:** The molecule is not cyclic, making it impossible to delocalize π electrons in a ring. - **Conclusion:** This compound is non-aromatic because it is not a cyclic structure and therefore does not meet the criteria for aromaticity or antiaromaticity. By analyzing the structure and using Huckel's rule,
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