Explain how you would get an enthalpy of formation that is greater than zero using the magnitudes of the bond enthalpies and equation 9.3 (given in the image attached)

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Explain how you would get an enthalpy of formation that is greater than zero using the magnitudes of the bond enthalpies and equation 9.3 (given in the image attached)

The equation presented here represents the calculation for the change in enthalpy (\(\Delta H^\circ\)) during a chemical reaction, based on bond enthalpies:

\[
\Delta H^\circ = \Sigma \text{BE (reactants)} - \Sigma \text{BE (products)}
\]
\[
= \text{total energy input} - \text{total energy released}
\]

Where:
- \(\Sigma\) stands for the summation sign, indicating the summation of bond enthalpies.
- \(\text{BE}\) represents the bond enthalpy.
- The equation expresses that the change in enthalpy is the difference between the total bond energies required to break the bonds in the reactants and the total energy released when bonds are formed in the products.

There are no graphs or diagrams accompanying this equation.
Transcribed Image Text:The equation presented here represents the calculation for the change in enthalpy (\(\Delta H^\circ\)) during a chemical reaction, based on bond enthalpies: \[ \Delta H^\circ = \Sigma \text{BE (reactants)} - \Sigma \text{BE (products)} \] \[ = \text{total energy input} - \text{total energy released} \] Where: - \(\Sigma\) stands for the summation sign, indicating the summation of bond enthalpies. - \(\text{BE}\) represents the bond enthalpy. - The equation expresses that the change in enthalpy is the difference between the total bond energies required to break the bonds in the reactants and the total energy released when bonds are formed in the products. There are no graphs or diagrams accompanying this equation.
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