Experiments on learning in animals sometimes measure how long it takes mice to find their way through a maze. The mean timeis 18 seconds for one particular maze. A researcher thinks that a loud noise will cause the mice to complete the maze faster. Shemeasures how long each of 10 mice takes with a loud noise as stimulus.The appropriate hypotheses for the significance test areO Ho : µ < 18; Ha : µ = 18.Но : и %3D 18; На : и + 18.aНо : и 3D 18; На : и < 18.aО Но : и 3 18; На : и > 18.

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Answered: Experiments on learning in animals…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Dogsled drivers, known as mushers, use several different breeds of dogs to pull their sleds. One proponent of Siberian Huskies believes that sleds pulled by Siberian Huskies are faster than sleds pulled by other breeds. He times 4040 teams of Siberian Huskies on a particular short course, and they have a mean time of 7.77.7 minutes. The mean time on the same course for 4747 teams of other breeds of sled dogs is 6.26.2 minutes. Assume that the times on this course have a population standard deviation of 1.51.5 minutes for teams of Siberian Huskies and 1.61.6 minutes for teams of other breeds of sled dogs. Let Population 1 be sleds pulled by Siberian Huskies and let Population 2 be sleds pulled by other breeds. Step 1 of 2 : Construct a 95%95% confidence interval for the true difference between the mean times on this course for teams of Siberian Huskies and teams of other breeds of sled dogs. Round the endpoints of the interval to one decimal place, if necessary.
The mean height of a certain kind of plant is 170 centimeters. Suppose we want to carry out a hypothesis test to see if the mean height when these plants are treated with a certain chemical differs from 170. State the null hypothesis H0 and the alternative hypothesis H1 that we would use for this test.
A researcher wants to examine the effect of daily mental exercises on cognitive performance of people in early stages of Alzheimer's disease. She enrolled to her study n = 16 patients diagnosed with the early stage of Alzheimer's disease and all participants conducted daily mental exercises for a month. At the end of the program all enrolled patients took the MMSE test (i.e., Mini-Mental State Examination). The results show that the sample mean on the MMSE test was M = 23.6 with the standard deviation, s = 7. It is known that the MMSE mean in the population of patients with early Alzheimer's disease is µ = 20. Do these data show a significant effect of daily mental exercises on cognitive performance in early stages of Alzheimer's disease?
Part 1 of 4 A doctor in Oklahoma City wants to know whether the average life span for heart disease patients at four hospitals in the city differ. The data below represents the life span, in years, of heart disease patients from each hospital. Perform an ANOVA test with a 10% level of significance to test whether the average life span of heart disease patients in Oklahoma City differs depending on the hospital that treats them Life Span of Patients Treated at Hospital 1: 8.1, 1.2, 7, 11.5, 21, 2, 15.3, 19.2, 10.5, 15.4, 12.7, 15.3, 12.1, 7.5, 11.4, 16.4, 26.7, 14.6, 1.5, 16.3, 12.6, 0.8, 18.2, 4.2, 9.6, 21, 16.3, 2.7 Life Span of Patients Treated at Hospital 2: 17.6, 11.6, 16.8, 5.2, 6.7, 3.2, 13.8, 12.5, 0.9, 6, 14.3, 1.8, 14.8, 10, 5.8, 15.2, 10, 3.7, 11.4, 21.6, 12.9, 0.5, 9.2, 13.9, 10.9 Life Span of Patients Treated at Hospital 3: 8.5, 2.3, 11, 7.4, 14.8, 5.8, 11, 3.4, 10.9, 1.1, 5.9, 21.6, 12.5, 0.1, 15.5, 15.4, 0.8, 7.7, 5.6, 12, 7.1 Life Span of Patients Treated at Hospital 4:…
A man who moves to a new city sees that there are two routes he could take to work. A neighbor who has lived there a long time tells him Route A will average 5 minutes faster than Route B. The man decides to experiment. Each day he flips a coin to determine which way to go, driving each route 20 days. He finds that Route A takes an average of 45 minutes, with standard deviation 3 minutes, and Route B takes an average of 49 minutes, with standard deviation 5 minutes. Histograms of travel times for the routes are roughly symmetric and show no outliers. Complete parts a and b. (...) a) Find a 95% confidence interval for the difference between the Route B and Route A commuting times, (µÂ ¯ µÃ) - The confidence interval is (.). (Round to two decimal places as needed.)
Suppose that Kim is a participant in a study that compares several coaching methods to see how they affect math Scholar Aptitude Test (SAT) scores. The grand mean of math SAT scores for all participants (My) in the study is 550. The group that Kim participated in had a mean math SAT score of 565. Kim’s individual score on the math SAT was 610. What was the estimate residual component (of Kim’s score, that is, the part of Kim’s score that was not related to the coaching method? (Both parts of this question call for specific numerical values as answers). What was that “effect” (ai) component of Kim's score? What pattern in grouped data would make SSwithin = 0? What pattern within data would make SSbetween = 0?
SHOW STEP BY STEP. pls
The wrong alternative. One of your friends is testing the effect of drinking coffee on the duration of cold symptoms. The common cold lasts, on average, 6 days. Your friend starts with no expectations as to whether drinking coffee will have any effect on cold duration. After seeing the results of the experiment, in which the average cold duration was less than 6 days, your friend tests a one-sided alternative about the population mean cold duration when drinking coffee, H0: lcoffee = 6 На: Which gives a one-sided P value P = 0.0465. Explain why your friend should have used a two-sided hypothesis. Hcoffee < 6

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