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Experiment 6: Redox Titrations (Iodine Titrations) Calculate the concentration of sodium thiosulfate (158.11 g/mol) solution in g/L. if 0.200g of KIO3 (214.00 g/mol) required 60.0 mL of the thiosulfate solution in the presence of excess of KI and H₂SO₂? KIO, +5KI + 3H₂SO4 -3H₂O + 31₂ +3K₂SO4 2Na₂S₂O3 + 1₂ → Na₂S₂O6 + 21- a) 17.7 g/L b) 22.2/L c) 14.8 g/L d) 29.6 g/L e) 12.7 g/L

Experiment 6: Redox Titrations (Iodine Titrations) Calculate the concentration of sodium thiosulfate (158.11 g/mol) solution in g/L. if 0.200g of KIO3 (214.00 g/mol) required 60.0 mL of the thiosulfate solution in the presence of excess of KI and H₂SO₂? KIO, +5KI + 3H₂SO4 -3H₂O + 31₂ +3K₂SO4 2Na₂S₂O3 + 1₂ → Na₂S₂O6 + 21- a) 17.7 g/L b) 22.2/L c) 14.8 g/L d) 29.6 g/L e) 12.7 g/L

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calculate the concentration of sodium thiosulfate (158.11 g/mol) solution in g/L if 0.200g of KIO, (214.00 g/mol) required 60.0 mL of the thiosulfate solution in the presence of excess of KI and H₂SO,?

Experiment 6: Redox Titrations (Iodine Titrations) Calculate the concentration of sodium thiosulfate (158.11 g/mol) solution in g/L. if 0.200g of KIO3 (214.00 g/mol) required 60.0 mL of the thiosulfate solution in the presence of excess of KI and H₂SO₂ ? KIO, +5KI + 3H₂SO 3H₂O + 31₂ +3K₂SO4 2Na₂S₂O3 + 1₂ → Na₂S₂O6 +21- a) 17.7 g/L b) 22.2/L c) 14.8 g/L d) 29.6 g/L e) 12.7 g/L
Transcribed Image Text:Experiment 6: Redox Titrations (Iodine Titrations) Calculate the concentration of sodium thiosulfate (158.11 g/mol) solution in g/L. if 0.200g of KIO3 (214.00 g/mol) required 60.0 mL of the thiosulfate solution in the presence of excess of KI and H₂SO₂ ? KIO, +5KI + 3H₂SO 3H₂O + 31₂ +3K₂SO4 2Na₂S₂O3 + 1₂ → Na₂S₂O6 +21- a) 17.7 g/L b) 22.2/L c) 14.8 g/L d) 29.6 g/L e) 12.7 g/L
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