How many mL of 0.789 M HI are needed to dissolve 9.52 g of MgCO3?2HI(aq) + MgCO3(s) MgI2(aq) + H2O(l) + CO2(g)

Given ; molarity of HI = 0.788 M Mass of MgCO3 = 9.52 g

Answered: How many mL of 0.789 M HI are needed to…

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How many mL of 0.789 M HI are needed to dissolve 9.52 g of MgCO3?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

How many mL of 0.789 M HI are needed to dissolve 9.52 g of MgCO₃?

2HI(aq) + MgCO₃(s) MgI₂(aq) + H₂O(l) + CO₂(g)

Expert Solution

Step 1

Given ; molarity of HI = 0.788 M

Mass of MgCO₃= 9.52 g

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