Experiment 5: Generating Hydrogen Gas Part B: Molar mass of unknown metal Mass of unknown metal (X): Volume of H₂ gas Temperature of H₂ gas Atmospheric pressure (see barometer) Vapor pressure of water Partial pressure of H₂ gas 746.5mmHg-/6.5mmHg = 730 mmHg Using PV=nRT and your data, calculate the moles of hydrogen gas produced in the experiment: (0.96atm)(0.019L) V=19.0mL latm molk ;)(292K) 35-2 158 P=746.5mmHg T: 292K 273+19.0=292° Unknown #: TEPYO 0: 2017CA10.0 0.1307 19.0 19.0 g mL °℃ 0.019 292 746.5 mmHg 16.5 mmHg 0.0217 730.0 mmHg 0.961 moles H₂: atm latm: 760mmHg 07anaje 19.0m₂ x IL 2 1000ML 0.019L 1000mL Convert moles of hydrogen gas to moles of the metal (X), using the balanced equation. X (s) + 2 HCl (aq) → XCl₂2 (aq) + H₂ (g) 0.000/6₂1 marx = 0.0000 lot% (XSPS) IMOLK Calculate the molar mass of the metal (g/mol) and identify the metal. 0.3079x1759 ginal 0.000769x L 0.00076 mol X moles X: K R=0.0821 LC m Metal: 0.00076 Molar mass: 171.97

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Experiment 5: Generating Hydrogen Gas
m:7609
Part B: Molar mass of unknown metal
Mass of unknown metal (X):
Volume of H₂ gas
Temperature of H₂ gas
Atmospheric pressure (see barometer)
Vapor pressure of water
Partial pressure of H₂ gas
746.5mmHg- /6.5mmHg = 730 mmHg
Using PV=nRT and your data, calculate the moles of hydrogen gas produced in the
experiment:
(0.96atm)(0.0194)
V=19.0mL
latm
molk
;)(292K)
2:52 158
P=746.5mmHg
T: 292K
273+19.0=292°
TEPTO 0:
Unknown #:
201310.0
g
0.3019x
0.000769x
0.1307
19.0
19.0
746.5 mmHg
16.5 mmHg 0.0217
730.0 mmHg 0.961
mL
°℃
0.019
292
moles H₂:
drenaje
19.0m₂ x
IL
2 1000ML
0.019L
1000mL
Convert moles of hydrogen gas to moles of the metal (X), using the balanced equation.
X (s) + 2 HCl (aq) → XCl₂2 (aq) + H₂ (g)
0.000/m1 maix
= 0.0000 101%
(XSPS)
IMOLK
Calculate the molar mass of the metal (g/mol) and identify the metal.
3079x75gin61
atm
latm: 760mmHg
L
0.00076molX
moles X:
K
R=0.0821 LC
m
Metal:
0.00076
Molar mass: 171.97
Transcribed Image Text:Experiment 5: Generating Hydrogen Gas m:7609 Part B: Molar mass of unknown metal Mass of unknown metal (X): Volume of H₂ gas Temperature of H₂ gas Atmospheric pressure (see barometer) Vapor pressure of water Partial pressure of H₂ gas 746.5mmHg- /6.5mmHg = 730 mmHg Using PV=nRT and your data, calculate the moles of hydrogen gas produced in the experiment: (0.96atm)(0.0194) V=19.0mL latm molk ;)(292K) 2:52 158 P=746.5mmHg T: 292K 273+19.0=292° TEPTO 0: Unknown #: 201310.0 g 0.3019x 0.000769x 0.1307 19.0 19.0 746.5 mmHg 16.5 mmHg 0.0217 730.0 mmHg 0.961 mL °℃ 0.019 292 moles H₂: drenaje 19.0m₂ x IL 2 1000ML 0.019L 1000mL Convert moles of hydrogen gas to moles of the metal (X), using the balanced equation. X (s) + 2 HCl (aq) → XCl₂2 (aq) + H₂ (g) 0.000/m1 maix = 0.0000 101% (XSPS) IMOLK Calculate the molar mass of the metal (g/mol) and identify the metal. 3079x75gin61 atm latm: 760mmHg L 0.00076molX moles X: K R=0.0821 LC m Metal: 0.00076 Molar mass: 171.97
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