Experiment (3) Newton's Second Law ;الاسم الرقم الجامعي الشعبة PART (I): CONSTANT NET FORCE Data and results Table 1 (m,-m;= 20g) y=(1±0.0005)m Trialm, (gm, (g (m,+m) 1,(s) ) , (s) (s) 0.01s0.01s0.01s0.01 120 094 107 142 126 1.25 1.58 124 141 171 147 1.4 182 134 L67 (g) (m's) 70 29070 90 50 3110 130 110 0 S150 130 Slope = . ... ..... ( Question (1): From the slope calculate the gravity acceleration g. Question (2): Calculate the absolute and relative error in the (gravity acceleration (g PART (II): CONSTANT MASS Data and results Table 2 (m,+m,= 200g) Trialm,(gm, (g (m,-m) (g L(s)49, () y=(1±0.0005)m 0.01s0.01s0.010.01 (m's') I 150 60 3130 120 50 0.75 72 140 074 70 0.92 2 1.05 067 L12 0.93 L19 S110 90 132 1.69 1.5 Slope = .. . ( Question (1): From the slope calculate the gravity acceleration g. Question (2): Calculate the absolute and relative error in the (gravity acceleration (g
Experiment (3) Newton's Second Law ;الاسم الرقم الجامعي الشعبة PART (I): CONSTANT NET FORCE Data and results Table 1 (m,-m;= 20g) y=(1±0.0005)m Trialm, (gm, (g (m,+m) 1,(s) ) , (s) (s) 0.01s0.01s0.01s0.01 120 094 107 142 126 1.25 1.58 124 141 171 147 1.4 182 134 L67 (g) (m's) 70 29070 90 50 3110 130 110 0 S150 130 Slope = . ... ..... ( Question (1): From the slope calculate the gravity acceleration g. Question (2): Calculate the absolute and relative error in the (gravity acceleration (g PART (II): CONSTANT MASS Data and results Table 2 (m,+m,= 200g) Trialm,(gm, (g (m,-m) (g L(s)49, () y=(1±0.0005)m 0.01s0.01s0.010.01 (m's') I 150 60 3130 120 50 0.75 72 140 074 70 0.92 2 1.05 067 L12 0.93 L19 S110 90 132 1.69 1.5 Slope = .. . ( Question (1): From the slope calculate the gravity acceleration g. Question (2): Calculate the absolute and relative error in the (gravity acceleration (g
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B4
![Experiment (3)
Newton's Second Law
:الاسم الرقم الجامعي الشعبة
PART (I): CONSTANT NET FORCE
Data and results
Table 1
(m,-m,= 20g)
Trialm, (g)m, (g) 1/(m,+m,) 1,(s)(s) t, (s) (s)
y=(1±0.0005)m
0.01s0.01s0.01s0.01s
120 0.94 1.07
126 1.25
(g)
|(m's')
70
50
2 90
3 110
4 130
S150
2
70
142
1.58 124
147
1.82 134 167
90
141
4
110
171
1.44
130
1.67
Slope = ..... . (
Question (1): From the slope calculate the gravity acceleration
g.
Question (2): Calculate the absolute and relative error in the
(gravity acceleration (g
PART (II): CONSTANT MASS
Data and results
Table 2
(m,+m2= 200g)
Trialm, (g)m, (gm,-m,) (g) t,(s) t(s) | t, (s)
y=(1±0.0005)m
(s) s a
|(m/s')
%3D
0.01s0.01s0.01s0.01s
150
2 140
50
0.57
0.75 0.72
0310.74
0.92 105 067
L.12
60
0.73
130
70
4120
S
80
0.93
L19
110
90
132
1.69
1.55
Slope =. .
*........ (
Question (1): From the slope calculate the gravity acceleration
g.
Question (2): Calculate the absolute and relative error in the
(gravity acceleration (g](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9c9d0bf6-af78-4df3-b8e1-467644b4b607%2Fe00d36b5-5508-43f9-9992-f5514d6008d0%2Fpapzir_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Experiment (3)
Newton's Second Law
:الاسم الرقم الجامعي الشعبة
PART (I): CONSTANT NET FORCE
Data and results
Table 1
(m,-m,= 20g)
Trialm, (g)m, (g) 1/(m,+m,) 1,(s)(s) t, (s) (s)
y=(1±0.0005)m
0.01s0.01s0.01s0.01s
120 0.94 1.07
126 1.25
(g)
|(m's')
70
50
2 90
3 110
4 130
S150
2
70
142
1.58 124
147
1.82 134 167
90
141
4
110
171
1.44
130
1.67
Slope = ..... . (
Question (1): From the slope calculate the gravity acceleration
g.
Question (2): Calculate the absolute and relative error in the
(gravity acceleration (g
PART (II): CONSTANT MASS
Data and results
Table 2
(m,+m2= 200g)
Trialm, (g)m, (gm,-m,) (g) t,(s) t(s) | t, (s)
y=(1±0.0005)m
(s) s a
|(m/s')
%3D
0.01s0.01s0.01s0.01s
150
2 140
50
0.57
0.75 0.72
0310.74
0.92 105 067
L.12
60
0.73
130
70
4120
S
80
0.93
L19
110
90
132
1.69
1.55
Slope =. .
*........ (
Question (1): From the slope calculate the gravity acceleration
g.
Question (2): Calculate the absolute and relative error in the
(gravity acceleration (g
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