Experiment 28 Advance Study Assignment: Determination of the Hardness of Water 1. A 0.3946 g sample of CaCO, is dissolved in 12 M HCI and the resulting solution is diluted to 250.0 mL in a volumetric flask. a. How many moles of CACO, are used (formula mass = 100.1)? moles b. What is the molarity of the Ca²* in the 250 mL of solution? M c. How many moles of Ca* are in a 25.00-mL aliquot of the solution in Ib? moles * moles of CacOs = Weight in gram formula mass 0-3946 1001 E3.942 x 10-3 mol Molanity moles of solute Volume of solution (L) 3.942 x 1o-3 x 1000 250 0.0158 M Imol Caco, produce. I mol Cat ion 0.0158 M Moles off Ca?+ = Molarity x 0.0158 Vo lume lin L) 25 1000 3.94 X10-4 mol.
Experiment 28 Advance Study Assignment: Determination of the Hardness of Water 1. A 0.3946 g sample of CaCO, is dissolved in 12 M HCI and the resulting solution is diluted to 250.0 mL in a volumetric flask. a. How many moles of CACO, are used (formula mass = 100.1)? moles b. What is the molarity of the Ca²* in the 250 mL of solution? M c. How many moles of Ca* are in a 25.00-mL aliquot of the solution in Ib? moles * moles of CacOs = Weight in gram formula mass 0-3946 1001 E3.942 x 10-3 mol Molanity moles of solute Volume of solution (L) 3.942 x 1o-3 x 1000 250 0.0158 M Imol Caco, produce. I mol Cat ion 0.0158 M Moles off Ca?+ = Molarity x 0.0158 Vo lume lin L) 25 1000 3.94 X10-4 mol.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Experiment 28
Advance Study Assignment: Determination of the Hardness of Water
1. A 0.3946 g sample of CaCO, is dissolved in 12 M HCI and the resulting solution is diluted to 250.0 mL
in a volumetric flask.
a. How many moles of CACO, are used (formula mass = 100.1)?
moles
b. What is the molarity of the Ca²* in the 250 mL of solution?
M
c. How many moles of Ca" are in a 25.00-mL aliquot of the solution in Ib?
moles
.. moles 아 Cacos 드
Weight in gram
formula mass
0-3946
1001
E3.942 x 10-3 mol
moles of solute
Molanity
Volume of solution (L)
3.942 x 1o-3
x 1000
250
0.0158 M
Imol Caco, produce
I mol
Cast ion
0.0158 M
Moles off Ca²+ =
Molarity x
0.0158
Vo lume lin L)
25
1000
3.94 X10-4mol.

Transcribed Image Text:moles
2. 25.00-mL aliquots of the solution from Problem I are titrated with EDTA to the Eriochrome Black T end
point. A blank containing a small measured amount of Mg requires 2.77 mL of the EDTA to reach the
end point. An aliquot to which the same amount of Mg is added requires 39.04 mL of the EDTA to
reach the end point.
a. How many milliliters of EDTA are needed to titrate the Ca* ion in the aliquot?
mL
b. How many moles of EDTA are there in the volume obtained in Part a?
moles
c. What is the molarity of the EDTA solution?
234
Experiment 28 Detemination of the Hardness of Water
3. A 100-mL sample of hard water is titrated with the EDTA solution in Problem 2. The same amount
Mg is added as previously, and the volume of EDTA required is 31.84 mL.
a. What volume of EDTA is used in titrating the Ca* in the hard water?
mL
b. How many moles of EDTA are there in that volume?
moles
c. How many moles of Ca are there in the 100 mL of water?
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