Sodium hydroxide reacts with acetic acid to produce sodium acetate and water. It takes 25.0 ml of 0.40 M NaOH to completely neutralize 50.0 ml of 0.20 M HC»H¿O, solution (i.e. to reach the equivalence point). What is the pH at the equivalence point (Ka (HC2H3O2) = 1.80 x 10*) 7.00 b. 9.11 a. с. 8.13 d. 8.93 e. 11.19
Sodium hydroxide reacts with acetic acid to produce sodium acetate and water. It takes 25.0 ml of 0.40 M NaOH to completely neutralize 50.0 ml of 0.20 M HC»H¿O, solution (i.e. to reach the equivalence point). What is the pH at the equivalence point (Ka (HC2H3O2) = 1.80 x 10*) 7.00 b. 9.11 a. с. 8.13 d. 8.93 e. 11.19
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Educational Chemistry Exercise**
1. **Equilibrium Problem:**
\[
\text{Hln} + \text{H}_2\text{O} \leftrightarrow \text{H}_3\text{O}^+ + \text{ln}^-
\]
If Hln is red and ln^- is green, what color will the solution be?
- a. red
- b. a mixture of red and green (i.e., yellow)
- c. none of the other answers
- d. green
2. **Titration Calculation:**
Sodium hydroxide reacts with acetic acid to produce sodium acetate and water. It takes 25.0 mL of 0.40 M NaOH to completely neutralize 50.0 mL of 0.20 M \(\text{HCH}_2\text{O}_2\) solution (i.e., to reach the equivalence point).
What is the pH at the equivalence point? (\(K_a\) for \(\text{CH}_2\text{O}_2\) = \(1.8 \times 10^{-5}\))
- a. 7.00
- b. 9.13
- c. 8.93
- d. 11.19
3. **Solubility and Acidity:**
Which of the following compounds will be more soluble in acidic solution than in pure water?
- a. \(\text{KClO}_4\)
- b. \(\text{CaCl}_2\)
- c. \(\text{KF}\) (basic, forms from KOH and HF)
- d. \(\text{CaI}_2\)
- e. \(\text{Fe(NO}_3\text{)}_2\)
4. **Acidic Solutions:**
Which of the following will form an acidic solution in water?
- a. \(\text{NH}_4\text{Cl}\)
- b. \(\text{KNO}_3\)
- c. \(\text{KCl}\)
- d. \(\text{NaCl}\)
- e. \(\text{Fe(NO}_3\text{)}_2\)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff02d8cd4-1b81-4491-920c-dd0abd3c7d66%2F7742a0f8-72c7-4a99-ad19-07d8f9000db8%2F25emmvf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Educational Chemistry Exercise**
1. **Equilibrium Problem:**
\[
\text{Hln} + \text{H}_2\text{O} \leftrightarrow \text{H}_3\text{O}^+ + \text{ln}^-
\]
If Hln is red and ln^- is green, what color will the solution be?
- a. red
- b. a mixture of red and green (i.e., yellow)
- c. none of the other answers
- d. green
2. **Titration Calculation:**
Sodium hydroxide reacts with acetic acid to produce sodium acetate and water. It takes 25.0 mL of 0.40 M NaOH to completely neutralize 50.0 mL of 0.20 M \(\text{HCH}_2\text{O}_2\) solution (i.e., to reach the equivalence point).
What is the pH at the equivalence point? (\(K_a\) for \(\text{CH}_2\text{O}_2\) = \(1.8 \times 10^{-5}\))
- a. 7.00
- b. 9.13
- c. 8.93
- d. 11.19
3. **Solubility and Acidity:**
Which of the following compounds will be more soluble in acidic solution than in pure water?
- a. \(\text{KClO}_4\)
- b. \(\text{CaCl}_2\)
- c. \(\text{KF}\) (basic, forms from KOH and HF)
- d. \(\text{CaI}_2\)
- e. \(\text{Fe(NO}_3\text{)}_2\)
4. **Acidic Solutions:**
Which of the following will form an acidic solution in water?
- a. \(\text{NH}_4\text{Cl}\)
- b. \(\text{KNO}_3\)
- c. \(\text{KCl}\)
- d. \(\text{NaCl}\)
- e. \(\text{Fe(NO}_3\text{)}_2\)
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