Experiment 11 Data to be completed and uploaded. Only one trial! (There is no part A) Part B. Standardization of Sodium hydroxide solution Balanced chemical equation: Trial 1 Trial 2 Trial 3 Mass of oxalic acid _0.1314g NA NA Initial burette reading 0.40mL 20.60mL Final burette reading 20.60 m -0.40 mL 20.20ML Volume NaOH added 20.20mL moles of oxalic acid 0:001m O.1314 3 = 0,00Im moles of NaOH added 0.002m 2x 0.00lm=0.002 Molarity of NaOH O.IM Volume 2020ML
Experiment 11 Data to be completed and uploaded. Only one trial! (There is no part A) Part B. Standardization of Sodium hydroxide solution Balanced chemical equation: Trial 1 Trial 2 Trial 3 Mass of oxalic acid _0.1314g NA NA Initial burette reading 0.40mL 20.60mL Final burette reading 20.60 m -0.40 mL 20.20ML Volume NaOH added 20.20mL moles of oxalic acid 0:001m O.1314 3 = 0,00Im moles of NaOH added 0.002m 2x 0.00lm=0.002 Molarity of NaOH O.IM Volume 2020ML
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:Experiment 11
Data to be completed and uploaded.
Only one trial!
(There is no part A)
Part B. Standardization of Sodium hydroxide solution
Balanced chemical equation:
Trial 1
Trial 2
Trial 3
Mass of oxalic acid
_0.1314g_
NA
NA
Initial burette reading
_0.40mL
Final burette reading
20.60 me
-0.40 mL
20.20 mL
Volume NaOH added
20.60mL
· 20.20mk
moles of oxalic acid
O.1314 g
moles
= 0.00Im
90g
つ11*メP
moles of NaOH added
Actd
0.002m
2x 0.00lm=0.002
Molarity of NaOH
of NaOH=melas
Volume
molavit
2020ML
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