Exp No. 1 2 3 Br₂ + H₂ [Br₂] (molecules/cm³) The reaction is.... 1.00E18 4.00E18 4.00E18 zero order in both [Br₂] and [H₂] 2HBr 1/2 order in [Br₂], 2nd order in [H₂] [H₂] (molecules/cm³) 1.00E19 1.00E19 2.00E19 1st order in [Br₂], 2nd order in [H₂], 3rd order overall Initial Rate (molecules/cm³/s) 4.71E15 9.42E15 1.88E16 1st order in [Br₂], 1st order in [H₂], 2nd order overall ½ order in [Br₂], 1st order in [H₂]
Exp No. 1 2 3 Br₂ + H₂ [Br₂] (molecules/cm³) The reaction is.... 1.00E18 4.00E18 4.00E18 zero order in both [Br₂] and [H₂] 2HBr 1/2 order in [Br₂], 2nd order in [H₂] [H₂] (molecules/cm³) 1.00E19 1.00E19 2.00E19 1st order in [Br₂], 2nd order in [H₂], 3rd order overall Initial Rate (molecules/cm³/s) 4.71E15 9.42E15 1.88E16 1st order in [Br₂], 1st order in [H₂], 2nd order overall ½ order in [Br₂], 1st order in [H₂]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![Exp No.
1
2
3
Br₂ + H₂ → 2HBr
[Br₂]
[H₂]
(molecules/cm³) (molecules/cm³)
The reaction is ....
1.00E18
4.00E18
4.00E18
zero order in both [Br₂] and [H₂]
1.00E19
1/2 order in [Br₂], 2nd order in [H₂]
1.00E19
2.00E19
1st order in [Br₂], 2nd order in [H₂], 3rd order overall
Initial Rate
(molecules/cm³/s)
4.71E15
9.42E15
1.88E16
1st order in [Br₂], 1st order in [H₂], 2nd order overall
½ order in [Br₂], 1st order in [H₂]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F706fa0bc-8b2b-46b5-9a0a-aff6b909f26f%2F8cd70a63-da36-4885-af76-533dc081c1c0%2Ft90mw6i_processed.png&w=3840&q=75)
Transcribed Image Text:Exp No.
1
2
3
Br₂ + H₂ → 2HBr
[Br₂]
[H₂]
(molecules/cm³) (molecules/cm³)
The reaction is ....
1.00E18
4.00E18
4.00E18
zero order in both [Br₂] and [H₂]
1.00E19
1/2 order in [Br₂], 2nd order in [H₂]
1.00E19
2.00E19
1st order in [Br₂], 2nd order in [H₂], 3rd order overall
Initial Rate
(molecules/cm³/s)
4.71E15
9.42E15
1.88E16
1st order in [Br₂], 1st order in [H₂], 2nd order overall
½ order in [Br₂], 1st order in [H₂]
Expert Solution

Step 1
Reaction given:-
Br2 + H2 => 2HBr
•We have to find out oreder of reaction regarding Br2 and H2.
•To find out degree regarding we use above given table.
Step by step
Solved in 4 steps
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