Enter your answer in the provided box. Consider the reaction: N₂(g) + 3H₂(g) -> 2NH3(g) Suppose that a particular moment during the reaction, molecular hydrogen is reacting with a magnitude of 0.0833 M/s. At what rate is molecular nitrogen reacting? 0.027 M/s

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### Reaction Rate Problem

**Consider the reaction:**

\[ \text{N}_2(g) + 3\text{H}_2(g) \rightarrow 2\text{NH}_3(g) \]

Suppose that at a particular moment during the reaction, molecular hydrogen is reacting with a magnitude of \(0.0833 \, \text{M/s}\). At what rate is molecular nitrogen reacting?

\[ \boxed{0.027 \, \text{M/s}} \]

**Explanation:**

Given:
- The rate of reaction for \(\text{H}_2\) is \(0.0833 \, \text{M/s}\).

The balanced chemical equation shows that one mole of \(\text{N}_2\) reacts with three moles of \(\text{H}_2\). Therefore, the rate of consumption of \(\text{N}_2\) is one-third the rate of consumption of \(\text{H}_2\).

\[ \text{Rate of } \text{N}_2 = \frac{1}{3} \times \text{Rate of } \text{H}_2 \]

\[ \text{Rate of } \text{N}_2 = \frac{1}{3} \times 0.0833 \, \text{M/s} = 0.0277 \, \text{M/s} \]

Rounding to three significant figures, the rate at which molecular nitrogen is reacting is \(\boxed{0.027 \, \text{M/s}}\).

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- **'3 attempts left':** Indicates the student has three remaining attempts to solve the problem correctly.
- **'Check my work' button:** Allows the student to submit their answer to see if it is correct.
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---

This structure provides a clear understanding of the problem, the chemical relationship involved, and the process used to find the rate at which molecular nitrogen reacts. It also explains the interface elements that assist students in solving the problem.
Transcribed Image Text:--- ### Reaction Rate Problem **Consider the reaction:** \[ \text{N}_2(g) + 3\text{H}_2(g) \rightarrow 2\text{NH}_3(g) \] Suppose that at a particular moment during the reaction, molecular hydrogen is reacting with a magnitude of \(0.0833 \, \text{M/s}\). At what rate is molecular nitrogen reacting? \[ \boxed{0.027 \, \text{M/s}} \] **Explanation:** Given: - The rate of reaction for \(\text{H}_2\) is \(0.0833 \, \text{M/s}\). The balanced chemical equation shows that one mole of \(\text{N}_2\) reacts with three moles of \(\text{H}_2\). Therefore, the rate of consumption of \(\text{N}_2\) is one-third the rate of consumption of \(\text{H}_2\). \[ \text{Rate of } \text{N}_2 = \frac{1}{3} \times \text{Rate of } \text{H}_2 \] \[ \text{Rate of } \text{N}_2 = \frac{1}{3} \times 0.0833 \, \text{M/s} = 0.0277 \, \text{M/s} \] Rounding to three significant figures, the rate at which molecular nitrogen is reacting is \(\boxed{0.027 \, \text{M/s}}\). ### Interface Description: - **'3 attempts left':** Indicates the student has three remaining attempts to solve the problem correctly. - **'Check my work' button:** Allows the student to submit their answer to see if it is correct. - **'Hint', 'Solution', 'Guided Solution' buttons:** Provides additional help if needed. - **Answer Input Box:** Space provided for students to enter the rate of reaction for molecular nitrogen. --- This structure provides a clear understanding of the problem, the chemical relationship involved, and the process used to find the rate at which molecular nitrogen reacts. It also explains the interface elements that assist students in solving the problem.
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