Exhibit 6-4 The starting salaries of individuals with an MBA degree are normally distributed with a mean of $40,000 and a standard deviation of $5,000. 8. Refer to Exhibit 6-4. What is the probability that a randomly selected individual with an MBA degree will get a starting salary of at least $47,500? .5000 .9332 .4332 .0668

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**Exhibit 6-4**

The starting salaries of individuals with an MBA degree are normally distributed with a mean of $40,000 and a standard deviation of $5,000.

**Question 8:**

Refer to Exhibit 6-4. What is the probability that a randomly selected individual with an MBA degree will get a starting salary of at least $47,500?

- ○ .5000
- ○ .9332
- ○ .4332
- ○ .0668

**Explanation:**

To solve this problem, we need to use the properties of the normal distribution. The question asks for the probability that a salary \( X \) is at least $47,500:

1. **Calculate the Z-score**:
   \[
   Z = \frac{X - \text{mean}}{\text{standard deviation}}
   \]
   where:
   - \( X = 47,500 \)
   - mean = 40,000
   - standard deviation = 5,000

2. **Interpret the Z-score**: The Z-score tells you how many standard deviations the value is from the mean.

3. **Probability Calculation**: Use the Z-score to find the probability from the standard normal distribution table (or a calculator with normal distribution functions).

4. **Select the Correct Answer**: Compare the calculated probability to the choices provided.
Transcribed Image Text:**Exhibit 6-4** The starting salaries of individuals with an MBA degree are normally distributed with a mean of $40,000 and a standard deviation of $5,000. **Question 8:** Refer to Exhibit 6-4. What is the probability that a randomly selected individual with an MBA degree will get a starting salary of at least $47,500? - ○ .5000 - ○ .9332 - ○ .4332 - ○ .0668 **Explanation:** To solve this problem, we need to use the properties of the normal distribution. The question asks for the probability that a salary \( X \) is at least $47,500: 1. **Calculate the Z-score**: \[ Z = \frac{X - \text{mean}}{\text{standard deviation}} \] where: - \( X = 47,500 \) - mean = 40,000 - standard deviation = 5,000 2. **Interpret the Z-score**: The Z-score tells you how many standard deviations the value is from the mean. 3. **Probability Calculation**: Use the Z-score to find the probability from the standard normal distribution table (or a calculator with normal distribution functions). 4. **Select the Correct Answer**: Compare the calculated probability to the choices provided.
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