Exhibit 8-1In order to estimate the average time spent on the computer terminals per studentat a local university, data were collected from a sample of 81 business students overa one-week period. Assume the population standard deviation is 1.2 hours.3. Refer to Exhibit 8-1. With a .95 probability, the margin of error is approximatelyO 1.96O.26O.211.64

Formula for margin of error (E) : E =zα/2×σn Where , zα/2 is critical value for given confidence…

Answered: In order to estimate the average time…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose that the lengths of pregnancies are normally distributed with a mean of 271 days and a standard deviation of 10 days. find the percentage of pregnancies that are longer than 254 days. For your intermediate computations, use four or more decimal places. Give your final answer to two decimal places (for example 98.23%).
7. Small newborn seal pups have a lower chance of survival. Suppose that the length of a newborn seal pup is a normal distribution with a mean length of 30.1 inches and a standard deviation of 1.3 inches. a. What is the probability that a newborn pup selected at random will be between 27 and 31 inches long? Include a sketch in your answer. Round to 3 decimal places. L= 30.1 ダ:1.3 27-31 inches 0.747 Normal celf (27,31,30.1, 1.3) b. G Draw a sketch of the normal curve that represents P90, the 90th percentile, then find the seal pup length that represents P90. Round to 1 decimal place. Pg 25 Standard deviation Value -mean EXTRA CREUT c. What would be the minimum length of seal pups in the top 2%, the very largest of them? Include a sketch. Round to 1 decimal place.
Assume the random variable X is normally distributed, with mean u= 44 and standard deviationo = 9. Find the 13th percentile.
Consider a normally distributed population with a mean of 196 and a standard deviation of 20. Find the value from this population that gives the 0.195 percentile. (Please round your answer to one decimal place, e.g. 0.6.)
A bottled water distributor wants to determine whether the mean amount of water contained in 1-gallon bottles purchased from a nationally known water bottling company is actually 1 gallon. You know from the water bottling company specifications that the standard deviation of the amount of water is 0.03 gallon. You select a random sample of 45 bottles, and the mean amount of water per 1-gallon bottle is 0.994 gallon. Complete parts (a) through (d) below. 1.96,-1.96 (Round to two decimal places as needed. Use a comma to separate answers as needed.) What is the final conclusion? A. Fail to reject Ho. There is not sufficient evidence that the mean amount is different from 1.0 gallon. OB. Reject Ho. There is not sufficient evidence to warrant rejection of the claim that the mean amount is different from 1.0 gallon. OC. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the mean amount is different from 1.0 gallon. D. Fail to reject Ho. There is sufficient…
A population of values has a mean of 38.5 and standard deviation of 80.4. Find the probability that a sample of 247 values from this population will have a mean between 31.3 and 44.1.
Assume that adults have IQ scores that are normally distributed with a mean of95.4 and a standard deviation of 16.6. Find the probability that a randomly selected adult has an IQ greater than 118.1 The probability that a randomly selected adult from this group has an IQ greater than 118.1 is what?
5. The mean birth weight for babies born one month early is 2630 grams. Assume that the population has a standard deviation of 220 grams. Sketch the distribution of birth weights (in grams) of children born one month early. Calculate probability of a child born one month early with a birth weight between 2100 grams and 2900 grams. Find the weight which corresponds to the top 25% of birth weights for babies born one month early.
A survey found that women's heights are normally distributed with mean 63.96 in and standard deviation 2.2 in. A branch of the military requires women's heights to be between 58 in and 80 in. a. Find the percentage of women meeting the height requirement. Are many women being denied the opportunity to join this branch of the military because they are too short or too tall? b. If this branch of the military changes the height requirements so that all women are eligible except the shortest 1% and the tallest 2%, what are the new height requirements?

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