Exercises1.2: Write an equation for each line described. 1. Passes through (-8,0) and (-1,3). 2. Passes through (2,-3)with slop 1/2. 3. Has slope -5/4 and y-intercept 6. 4. Passes through (-12, -9) and has slope 5. Passes through (1/3 , 4), and has no slo 6. Has y-intercept -6 and x-intercept 2 7. Passes through(-V2, 2)parallel to the lir

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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EXAMPLE 5
Calculating Distance
(a) The distance between P(-1, 2) and 0(3, 4) is
V(3 - (-1))² + (4 – 2) = V(4 + (2)² = V/20 = V4.5 = 2V5.
(b) The distance from the origin to P(x, y) is
V - 0)² + (y – o) = Vx² + y?.
21
Exercises1.2:
Write an equation for each line described.
1. Passes through (-8,0) and (-1,3).
2. Passes through (2,-3)with slop 1/2.
3. Has slope -5/4 and y-intercept 6 .
4. Passes through (-12, -9) and has slope 0.
5. Passes through (1/3 , 4), and has no slope.
6. Has y-intercept -6 and x-intercept 2
7. Passes through(-V2, 2)parallel to the line 2 x+ 5y= V3 .
8. Passes through(4,10) and is perpendicular to the line 6x - 3y=5.
22
Transcribed Image Text:EXAMPLE 5 Calculating Distance (a) The distance between P(-1, 2) and 0(3, 4) is V(3 - (-1))² + (4 – 2) = V(4 + (2)² = V/20 = V4.5 = 2V5. (b) The distance from the origin to P(x, y) is V - 0)² + (y – o) = Vx² + y?. 21 Exercises1.2: Write an equation for each line described. 1. Passes through (-8,0) and (-1,3). 2. Passes through (2,-3)with slop 1/2. 3. Has slope -5/4 and y-intercept 6 . 4. Passes through (-12, -9) and has slope 0. 5. Passes through (1/3 , 4), and has no slope. 6. Has y-intercept -6 and x-intercept 2 7. Passes through(-V2, 2)parallel to the line 2 x+ 5y= V3 . 8. Passes through(4,10) and is perpendicular to the line 6x - 3y=5. 22
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