Exercises: 1) A rigid tank contains 50 kg of saturated liquid water at 90°C. Determine the pressure in the tank and the volume of the tank. From tables at 90 "C, Psat 70.104kPa, vym0.001036 m/kg P=70.104 kPa V=0.001036 60kg = 0.06216 m²
Exercises: 1) A rigid tank contains 50 kg of saturated liquid water at 90°C. Determine the pressure in the tank and the volume of the tank. From tables at 90 "C, Psat 70.104kPa, vym0.001036 m/kg P=70.104 kPa V=0.001036 60kg = 0.06216 m²
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![Exercises:
1) A rigid tank contains 50 kg of saturated liquid water at 90°C.
Determine the pressure in the tank and the volume of the tank.
From tables at 90 "C, Psat 70.104kPa, v/ 0.001036 m/kg.
P=70.104 kPa
V=0.001036 * 60kg = 0.06216 m²³](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F23938311-cce6-459c-949d-2ac6dadc84ac%2Fcaf4be18-ec24-4a2b-8e1c-5c8e168cc152%2Fosu3p5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Exercises:
1) A rigid tank contains 50 kg of saturated liquid water at 90°C.
Determine the pressure in the tank and the volume of the tank.
From tables at 90 "C, Psat 70.104kPa, v/ 0.001036 m/kg.
P=70.104 kPa
V=0.001036 * 60kg = 0.06216 m²³
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