Exercise No. 1: Draw the shear and bending moment diagrams for girder AB. Also determine the maximum bending-moment. 2m P₁ ↓ 2m P₂ 4m P3 x 4th to the last digit 3rd to the last digit 2nd to the last digit Last digit 6m 4m P3 L=20 m Parameter = a + (b-a)x/10 where : x = student's ID digit number Parameter P₁ P₂ P3 P₁ 4m a 45 55 65 75 6m Pa b 50 60 70 80 P₁ 4m Units kN KN KN KN 2m P₂ 2m B d
Exercise No. 1: Draw the shear and bending moment diagrams for girder AB. Also determine the maximum bending-moment. 2m P₁ ↓ 2m P₂ 4m P3 x 4th to the last digit 3rd to the last digit 2nd to the last digit Last digit 6m 4m P3 L=20 m Parameter = a + (b-a)x/10 where : x = student's ID digit number Parameter P₁ P₂ P3 P₁ 4m a 45 55 65 75 6m Pa b 50 60 70 80 P₁ 4m Units kN KN KN KN 2m P₂ 2m B d
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Exercise 1: Draw the shear and bending-moment diagram for girder AB. Also determine the maximum bending-moment.
Where x = 2020100214
Note: Solve the exercise #1 problem with the same way and steps on how the sample problem #3 was solved.

Transcribed Image Text:Exercise No. 1: Draw the shear and bending moment diagrams for girder AB. Also
determine the maximum bending-moment.
2m
P₁
Į
2m
P₂
4m
P3
X
4th to the last digit
3rd to the last digit
2nd to the last digit
Last digit
6m
4m
P3
L=20 m
Parameter = a + (b-a)x/10
where : x = student's ID digit number
Parameter
P₁
P₂
P3
P4
4m
a
45
55
65
75
6m
Pa
b
50
60
70
80
P₁
4m
Units
KN
KN
kN
KN
2m
P₂
2m
B
d

Transcribed Image Text:SHEAR and MOMENT DIAGRAMS in BEAMS
Sample Problem No. 3: Draw the shear and bending moment diagrams for beam AB.
Also determine the maximum bending-moment. All pulleys have a 600 mm diameter.
Ax
Step 1: Draw the free body diagram
A
Ax = 50
Ay
50 kN
3m
45.78
Ay = 45.78
50 kN
Step 3: Forces Diagram
3m
3m
1ml
-4.22
C
7m
187.34
50
137.34
7m
Step 4: Shear and moment diagrams
50
Step 2: Compute the reactions at the support
ΣΕ= 0 ; - Ax + 50 = 0; Ax= 50 kN
ΣM₁ = 0; 50(3-.300)-50(1+. 300) - By(16.6) = 0 ; By = 4.22 kN
78 KN↑
ΣF, = 0; Ay+By-50=0; Ay= 45.78 KN
7m
-54.22
0.6m
50
0.6m
0.6m
1m
!1m
157.8
1m
Ý...
75.3
25.3
1m
1m
6m
50 kN
Step 5: Determine the maximum bending moment:
Therefore: Max. Moment=187.34 kN-m occur at point b.
6m
There are moments at c, d and e. M = 50 kN (1m) = 50 kN -m
Mc = 50 kN-m clockwise ; Md and Me = 50 kN-m counter clockwise
6m
50
By
B
B
-4.22
By = 4.22
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