Exercise Determine whether the sequence (an) given by an n³ 3n² - 2 converges, and find its limit if it does. Name any results or rules that you use. You may use the basic null sequences listed in Theorem D7 from Unit D2. n³ 3n²-1 (a) Explain why the following solution to this exercise is incorrect and/or incomplete, identifying three errors or significant omissions. For each error or omission, explain the mistake that the writer of the solution has made. (There may be more than three errors or omissions, but you need identify only three. These should not include statements or omissions that follows logically from earlier errors or omissions.) Solution (incorrect and/or incomplete!) For n=1,2,..., we have n³ 3n² - 2 n³ 3n²-2 n³ 3n2 - 2 lanl VI (since n³ 3n² 2n + + + 3n2 n³ n³ 3n²-1 n³ 3n² - 2 n³ 3n² n.³ 3n2 - 1 > 0 and (by the Triangle Inequality) n³ 3n² - 1 > 0)

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
Section: Chapter Questions
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This question concerns the following exercise.
Exercise
Determine whether the sequence (an) given by
n.³
n.³
an = 3n²2 - 2 3n² - 1
converges, and find its limit if it does. Name any results or rules that
you use. You may use the basic null sequences listed in Theorem D7
from Unit D2.
(a) Explain why the following solution to this exercise is incorrect and/or
incomplete, identifying three errors or significant omissions. For each
error or omission, explain the mistake that the writer of the solution
has made.
(There may be more than three errors or omissions, but you need
identify only three. These should not include statements or omissions
that follows logically from earlier errors or omissions.)
Solution (incorrect and/or incomplete!)
For n=1,2,..., we have
n.³
3n2 - 2
n³
3n² - 2
23
3n² - 2
|an|
73
VI
=
(since
n.³
3n²
2n
3
+
n³
3
3n²-1
+
n³
3n2 - 1
n³
3n2 - 1
+
n³
3n² - 2
n³
3n²
> 0 and
(by the Triangle Inequality)
n.³
3
3n² - 1
> 0)
Now 2n/3→ ∞o as noo, so by the Squeeze Rule
(Theorem D18) it follows that lan →∞ as n→∞0.
Therefore an →∞o as noo. Thus (an) is divergent.
(b) Write out a correct solution to the exercise.
Transcribed Image Text:This question concerns the following exercise. Exercise Determine whether the sequence (an) given by n.³ n.³ an = 3n²2 - 2 3n² - 1 converges, and find its limit if it does. Name any results or rules that you use. You may use the basic null sequences listed in Theorem D7 from Unit D2. (a) Explain why the following solution to this exercise is incorrect and/or incomplete, identifying three errors or significant omissions. For each error or omission, explain the mistake that the writer of the solution has made. (There may be more than three errors or omissions, but you need identify only three. These should not include statements or omissions that follows logically from earlier errors or omissions.) Solution (incorrect and/or incomplete!) For n=1,2,..., we have n.³ 3n2 - 2 n³ 3n² - 2 23 3n² - 2 |an| 73 VI = (since n.³ 3n² 2n 3 + n³ 3 3n²-1 + n³ 3n2 - 1 n³ 3n2 - 1 + n³ 3n² - 2 n³ 3n² > 0 and (by the Triangle Inequality) n.³ 3 3n² - 1 > 0) Now 2n/3→ ∞o as noo, so by the Squeeze Rule (Theorem D18) it follows that lan →∞ as n→∞0. Therefore an →∞o as noo. Thus (an) is divergent. (b) Write out a correct solution to the exercise.
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