Exercise Construct a titration curve by plotting pH vs. VNaOH added. HCl(aq) + NaOH(aq) H₂O(1) + NaCl(aq) Volume NaOH (mL) [H'] pH 0.00 5.00 10.00 15.00 20.00 25.00 30.00 35.00 40.00 45.00 48.00 50.00 52.00 55.00 60.00 65.00 70.00 75.00 80.00 85.00 90 95 100 1×10¹ Hints: The pH of the solution is calculated using the following equations: (a) Initial conditions (VNaOH = 0), [H"]=[HCI] (b) After initial addition of NaOH and before the end point: [H]=Mc-Man V V/ LV (c) At the end point (Vsaou 50 mL), all the HC1 is being consumed and the acidity of the solution comes from auto ionization of water which is: [H]-1-10 (d) After the end point: 1x 10-¹4 MXV NOW VO+VY [H"]= ABERDEELC titrant: NaOH, 0.IM Question 1) What is the pH when the solution volume in the flask reaches 95 ml? a. 12.79 b. 12.82 c. 1.95 d. 12. 75e. 2.28 Question2) What is the maximum pH reached at the end of titration? a. 12.77b. 12.79c. 12.81 d. 12. 78 e. 12.82 analyte: HC1, 0.1 M, 50 ml.

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter15: Acid–base Equilibria
Section: Chapter Questions
Problem 51P
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Exercise: Construct a titration curve by plotting pH vs. VNaOH added.
HCl(aq) + NaOH(aq)
H₂O(1) + NaCl(aq)
Volume NaOH (mL) [H] pH
0.00
5.00
10.00
15.00
20.00
25.00
30.00
35.00
40.00
45.00
48.00
50.00
52.00
55.00
60.00
65.00
70.00
75.00
80.00
85.00
90
95
100
1×10²
Hints:
The pH of the solution is calculated using the following equations:
(a) Initial conditions (VNaOH = 0), [H"]=[HCI]
(b) After initial addition of NaOH and before the end point:
[H]=MVMNVN
V/
LV
(c) At the end point (Vsaou 50 mL), all the HC1 is being consumed and the acidity
of the solution comes from auto ionization of water which is:
[H]-1-10
(d) After the end point:
1x 10-¹
XV
VO+VIRY
[H"]=
NOW
ABRIREDIC
titrant: NaOH, 0.1M
Question 1) What is the pH when the solution volume in the flask reaches 95
ml?
a. 12.79 b.12.82 c. 1.95 d. 12. 75e. 2.28
Question2) What is the maximum pH reached at the end of titration?
a. 12.77b. 12.79 c. 12.81 d. 12. 78 e. 12.82
analyte: HC1, 0.1 M, 50 ml.
Transcribed Image Text:Exercise: Construct a titration curve by plotting pH vs. VNaOH added. HCl(aq) + NaOH(aq) H₂O(1) + NaCl(aq) Volume NaOH (mL) [H] pH 0.00 5.00 10.00 15.00 20.00 25.00 30.00 35.00 40.00 45.00 48.00 50.00 52.00 55.00 60.00 65.00 70.00 75.00 80.00 85.00 90 95 100 1×10² Hints: The pH of the solution is calculated using the following equations: (a) Initial conditions (VNaOH = 0), [H"]=[HCI] (b) After initial addition of NaOH and before the end point: [H]=MVMNVN V/ LV (c) At the end point (Vsaou 50 mL), all the HC1 is being consumed and the acidity of the solution comes from auto ionization of water which is: [H]-1-10 (d) After the end point: 1x 10-¹ XV VO+VIRY [H"]= NOW ABRIREDIC titrant: NaOH, 0.1M Question 1) What is the pH when the solution volume in the flask reaches 95 ml? a. 12.79 b.12.82 c. 1.95 d. 12. 75e. 2.28 Question2) What is the maximum pH reached at the end of titration? a. 12.77b. 12.79 c. 12.81 d. 12. 78 e. 12.82 analyte: HC1, 0.1 M, 50 ml.
Exercise: Construct a titration curve by plotting pH vs. VNaOH added.
HCl(aq) + NaOH(aq)
H₂O(1) + NaCl(aq)
Volume NaOH (mL) [H] pH
0.00
5.00
10.00
15.00
20.00
25.00
30.00
35.00
40.00
45.00
48.00
50.00
52.00
55.00
60.00
65.00
70.00
75.00
80.00
85.00
90
95
100
1×10²
Hints:
The pH of the solution is calculated using the following equations:
(a) Initial conditions (VNaOH = 0), [H"]=[HCI]
(b) After initial addition of NaOH and before the end point:
[H]=MVMNVN
V/
LV
(c) At the end point (Vsaou 50 mL), all the HC1 is being consumed and the acidity
of the solution comes from auto ionization of water which is:
[H]-1-10
(d) After the end point:
1x 10-¹
XV
VO+VIRY
[H"]=
NOW
ABRIREDIC
titrant: NaOH, 0.1M
Question 1) What is the pH when the solution volume in the flask reaches 95
ml?
a. 12.79 b.12.82 c. 1.95 d. 12. 75e. 2.28
Question2) What is the maximum pH reached at the end of titration?
a. 12.77b. 12.79 c. 12.81 d. 12. 78 e. 12.82
analyte: HC1, 0.1 M, 50 ml.
Transcribed Image Text:Exercise: Construct a titration curve by plotting pH vs. VNaOH added. HCl(aq) + NaOH(aq) H₂O(1) + NaCl(aq) Volume NaOH (mL) [H] pH 0.00 5.00 10.00 15.00 20.00 25.00 30.00 35.00 40.00 45.00 48.00 50.00 52.00 55.00 60.00 65.00 70.00 75.00 80.00 85.00 90 95 100 1×10² Hints: The pH of the solution is calculated using the following equations: (a) Initial conditions (VNaOH = 0), [H"]=[HCI] (b) After initial addition of NaOH and before the end point: [H]=MVMNVN V/ LV (c) At the end point (Vsaou 50 mL), all the HC1 is being consumed and the acidity of the solution comes from auto ionization of water which is: [H]-1-10 (d) After the end point: 1x 10-¹ XV VO+VIRY [H"]= NOW ABRIREDIC titrant: NaOH, 0.1M Question 1) What is the pH when the solution volume in the flask reaches 95 ml? a. 12.79 b.12.82 c. 1.95 d. 12. 75e. 2.28 Question2) What is the maximum pH reached at the end of titration? a. 12.77b. 12.79 c. 12.81 d. 12. 78 e. 12.82 analyte: HC1, 0.1 M, 50 ml.
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