EXERCISE 7 Solve for x: noitsupo ods x² – 4x+3<0 (a) (1) - (3) x+7x2-12 (5) x² > 3x (7) x²-49 <0 (9) x² <9 (11) -x +3x-220 (13) -x² +4x50 (15) 2x2 - 3x+1<0
EXERCISE 7 Solve for x: noitsupo ods x² – 4x+3<0 (a) (1) - (3) x+7x2-12 (5) x² > 3x (7) x²-49 <0 (9) x² <9 (11) -x +3x-220 (13) -x² +4x50 (15) 2x2 - 3x+1<0
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Hello please help me with these questions they are really small but there is certain way you must do it I will put an example in the photos. Numbers 1,3,5 and 9 please they are really short the first picture is the example and the second the questions it is quadratic Inequalities. There must be a drawing
![EXERCISE 7
TARGAUO AO2
(a)
Solve for x:
(1)
x²-4x+3<0
(2)
22-2x-320
x² +7x2-12
(3)
x²> 3x
x² -12x<-20
3x2 - 2x<0
x²>1
(4)
(5)
(6)
x² – 49 <0
(7)
x² <9
-x² + 3x-220
-x² + 4x 50
2x2 - 3x+1<0
(8)
-x² <-4
x²+5x<6
(9)
(10)
(11)
(12)
(13)
(14)
2x2 +6x>-4
(15)
(16)
-3x2 + 4xS-4
(b)
Solve for x, in surd form:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6169cbba-79e8-49f7-a3ed-8edc7c55b748%2F15067d39-2a36-40f2-bbd5-7e66ff18bf84%2Fc4wfqj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:EXERCISE 7
TARGAUO AO2
(a)
Solve for x:
(1)
x²-4x+3<0
(2)
22-2x-320
x² +7x2-12
(3)
x²> 3x
x² -12x<-20
3x2 - 2x<0
x²>1
(4)
(5)
(6)
x² – 49 <0
(7)
x² <9
-x² + 3x-220
-x² + 4x 50
2x2 - 3x+1<0
(8)
-x² <-4
x²+5x<6
(9)
(10)
(11)
(12)
(13)
(14)
2x2 +6x>-4
(15)
(16)
-3x2 + 4xS-4
(b)
Solve for x, in surd form:
![EXAMPLE 12
Solve for x:
(b)
3x2 -2.x S1
(a)
-x² +5x+6<0
Solution
-x² +5x+6<0
:x-5x-6>0
(a)
+-1 and change direction of inequality
x²- 5x-6=0
(x-6)(x+1)=0
x=6 or x=-1
Critical Values:
050
>0
>0
<0
Final Solution: x<-1
or x>6
abon's
3x - 2x<1
3x2 – 2x-1<0
(b)
Critical Values:
3x2 - 2x-1=0
(3x+1)(x-1)= 0
1
or
x=--
x= 1
>0
>0
Final Solution:
13](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6169cbba-79e8-49f7-a3ed-8edc7c55b748%2F15067d39-2a36-40f2-bbd5-7e66ff18bf84%2Fen7bixk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:EXAMPLE 12
Solve for x:
(b)
3x2 -2.x S1
(a)
-x² +5x+6<0
Solution
-x² +5x+6<0
:x-5x-6>0
(a)
+-1 and change direction of inequality
x²- 5x-6=0
(x-6)(x+1)=0
x=6 or x=-1
Critical Values:
050
>0
>0
<0
Final Solution: x<-1
or x>6
abon's
3x - 2x<1
3x2 – 2x-1<0
(b)
Critical Values:
3x2 - 2x-1=0
(3x+1)(x-1)= 0
1
or
x=--
x= 1
>0
>0
Final Solution:
13
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