Hello there, can you help me solve this problem? Thanks! Let A =1 - 4 - 3301 3- 32and b =b2Show that the equation Ax = b does not have a solution for all possible b, and describe theb3set of all b for which Ax=b does have a solution.How can it be shown that the equation Ax = b does not have a solution for all possible b? Choose the correct answer below.A. Row reduce the matrix A to demonstrate that A has a pivot position in every row.B.Row reduce the augmented matrix [ A b ] to demonstrate that [ A b[Ab] hashas a pivot position in every row.C. Row reduce the matrix A to demonstrate that A does not have a pivot position in every row.D. Find a vector b for which the solution to Ax = b is the zero vector.E. Find a vector x for which Ax=b is the zero vector.Describe the set of all b for which Ax=b does have a solution.0=(Type an expression using b₁, b2, and b3 as the variables and 1 as the coefficient of b3.)

Answered: Let A = 1-4-3 3 0 1 3 - 3 2 and b = b₁…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Related questions

Question

Hello there, can you help me solve this problem? Thanks!

Let A =
1 - 4 - 3
3
0
1 3
- 3
2
and b =
b2
Show that the equation Ax = b does not have a solution for all possible b, and describe the
b3
set of all b for which Ax=b does have a solution.
How can it be shown that the equation Ax = b does not have a solution for all possible b? Choose the correct answer below.
A. Row reduce the matrix A to demonstrate that A has a pivot position in every row.
B.
Row reduce the augmented matrix [ A b ] to demonstrate that [ A b
[Ab] has
has a pivot position in every row.
C. Row reduce the matrix A to demonstrate that A does not have a pivot position in every row.
D. Find a vector b for which the solution to Ax = b is the zero vector.
E. Find a vector x for which Ax=b is the zero vector.
Describe the set of all b for which Ax=b does have a solution.
0=
(Type an expression using b₁, b2, and b3 as the variables and 1 as the coefficient of b3.)

Expert Solution

Step 1: Given the information

Given that $A equals open square brackets table row 1 cell negative 4 end cell cell negative 3 end cell row cell negative 3 end cell 3 0 row 2 1 3 end table close square brackets$ and $b equals open square brackets table row cell b subscript 1 end cell row cell b subscript 2 end cell row cell b subscript 3 end cell end table close square brackets$ .

The aim is to find the condition for which the system $A x equals b$ have a solution.