Exercise 4: Recall that in Exercise 3 we looked at Euler's method applied to the equation x = x with initial condition x(0) = 1. Suppose that our error tolerance is € = 0.003. Let's see when our h = 0.1 Euler approximation might run into trouble with this. (1) Calculate a new Euler approximation for x(0.1) using h = 0.05 (you'll now have two steps). What's the difference between your approxima- tions for x(0.1) using h= 0.1 and h= 0.05? Is it less than €? (2) If the difference is less than £, we assume that the solution with the larger h is fine at t = 0.1. (This should be the case!) Calculate a new estimate for x(0.2) using the initial condition x(0.1) = 1.1 (the
Exercise 4: Recall that in Exercise 3 we looked at Euler's method applied to the equation x = x with initial condition x(0) = 1. Suppose that our error tolerance is € = 0.003. Let's see when our h = 0.1 Euler approximation might run into trouble with this. (1) Calculate a new Euler approximation for x(0.1) using h = 0.05 (you'll now have two steps). What's the difference between your approxima- tions for x(0.1) using h= 0.1 and h= 0.05? Is it less than €? (2) If the difference is less than £, we assume that the solution with the larger h is fine at t = 0.1. (This should be the case!) Calculate a new estimate for x(0.2) using the initial condition x(0.1) = 1.1 (the
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Please show all work for exercise #4!
![estimate using h = 0.1) and a step size of h = 0.05. Is the difference
between the h = 0.1 and h= 0.05 approximations still less than e?
(3) If it is (it should be), do two more steps with h = 0.05, again starting
with the value for x(0.2) given by the Euler calculation with h = 0.1.
Notice that the error at the end of this step is bigger than €: this would
results in an adaptive stepsize routine decreasing the step size to be
sure that the error is in check.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5ea01508-f9b6-4a19-b038-56e12c298daf%2F68ac1b0a-12d4-423b-b3f0-4e2f3cda8137%2Frz6fs76_processed.png&w=3840&q=75)
Transcribed Image Text:estimate using h = 0.1) and a step size of h = 0.05. Is the difference
between the h = 0.1 and h= 0.05 approximations still less than e?
(3) If it is (it should be), do two more steps with h = 0.05, again starting
with the value for x(0.2) given by the Euler calculation with h = 0.1.
Notice that the error at the end of this step is bigger than €: this would
results in an adaptive stepsize routine decreasing the step size to be
sure that the error is in check.
![Exercise 4: Recall that in Exercise 3 we looked at Euler's method applied
to the equation x' = x with initial condition x(0) = 1. Suppose that
our error tolerance is € = 0.003. Let's see when our h = 0.1 Euler
approximation might run into trouble with this.
(1) Calculate a new Euler approximation for x(0.1) using h = 0.05 (you'll
now have two steps). What's the difference between your approxima-
tions for x(0.1) using h= 0.1 and h= 0.05? Is it less than €?
(2) If the difference is less than , we assume that the solution with the
larger h is fine at t = 0.1. (This should be the case!) Calculate a
new estimate for x(0.2) using the initial condition x(0.1) = 1.1 (the](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5ea01508-f9b6-4a19-b038-56e12c298daf%2F68ac1b0a-12d4-423b-b3f0-4e2f3cda8137%2Fzonb34e_processed.png&w=3840&q=75)
Transcribed Image Text:Exercise 4: Recall that in Exercise 3 we looked at Euler's method applied
to the equation x' = x with initial condition x(0) = 1. Suppose that
our error tolerance is € = 0.003. Let's see when our h = 0.1 Euler
approximation might run into trouble with this.
(1) Calculate a new Euler approximation for x(0.1) using h = 0.05 (you'll
now have two steps). What's the difference between your approxima-
tions for x(0.1) using h= 0.1 and h= 0.05? Is it less than €?
(2) If the difference is less than , we assume that the solution with the
larger h is fine at t = 0.1. (This should be the case!) Calculate a
new estimate for x(0.2) using the initial condition x(0.1) = 1.1 (the
Expert Solution
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