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EXERCISE 3.19 The radius of the inner conductor of a long coaxial cable is a. The inner radius of the outer conductor is b. If the inner and outer conductors are kept at potentials and 0 respectively, determine the electric potential and the electric field intensity in the insulating material by solving Laplace's equation. ANS. - In(br) Intba). E a,, --Intè ai If the problem is such that electric potential changes only in the circumferential direction and not in r- and 2-directions. Eq. (3-136) reduces to

EXERCISE 3.19 The radius of the inner conductor of a long coaxial cable is a. The inner radius of the outer conductor is b. If the inner and outer conductors are kept at potentials and 0 respectively, determine the electric potential and the electric field intensity in the insulating material by solving Laplace's equation. ANS. - In(br) Intba). E a,, --Intè ai If the problem is such that electric potential changes only in the circumferential direction and not in r- and 2-directions. Eq. (3-136) reduces to

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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EXERCISE 3.19 The radius of the inner conductor of a long coaxial cable is 2. The inner radius of the outer conductor is b. If the inner and outer conductors are kept at potentials, and 0 respectively, determine the electric potential and the electric field intensity in the insulating material by solving Laplace's equation. ANS. Inby Intbau E-Inai If the problem is such that electric potential changes only in the circumferential direction and not in r- and 2-directions. Eq. (3-136 reduces to 3-11 SOLUTION OF ELECTROSTATIC BOUNDARY-VALUE PROBLEMS 133 16² -0 We illustrate this case with the following example. (3-139)
Transcribed Image Text:EXERCISE 3.19 The radius of the inner conductor of a long coaxial cable is 2. The inner radius of the outer conductor is b. If the inner and outer conductors are kept at potentials, and 0 respectively, determine the electric potential and the electric field intensity in the insulating material by solving Laplace's equation. ANS. Inby Intbau E-Inai If the problem is such that electric potential changes only in the circumferential direction and not in r- and 2-directions. Eq. (3-136 reduces to 3-11 SOLUTION OF ELECTROSTATIC BOUNDARY-VALUE PROBLEMS 133 16² -0 We illustrate this case with the following example. (3-139)
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