Exercise 3.1. Let G be a group. Given g € G, define ig : G → G by ig(x)=gxg, Vx Є G. (1) Show that i, is an isomorphism of G with itself (i.e. an automorphism of G). (2) Show that CG(g) = {x G | ig(x) = x} = {x = G | xg = gx} is a subgroup of G, called the centralizer of g in G.
Exercise 3.1. Let G be a group. Given g € G, define ig : G → G by ig(x)=gxg, Vx Є G. (1) Show that i, is an isomorphism of G with itself (i.e. an automorphism of G). (2) Show that CG(g) = {x G | ig(x) = x} = {x = G | xg = gx} is a subgroup of G, called the centralizer of g in G.
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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
Transcribed Image Text:Exercise 3.1. Let G be a group. Given g € G, define ig : G → G by
ig(x)=gxg, Vx Є G.
(1) Show that i, is an isomorphism of G with itself (i.e. an automorphism of G).
(2) Show that
CG(g) = {x G | ig(x) = x} = {x = G | xg = gx}
is a subgroup of G, called the centralizer of g in G.
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