**Example 27.7 Power in an Electric Heater****Problem:**An electric heater is constructed by applying a potential difference of 120 V to a Nichrome wire that has a total resistance of 7.00 Ω. Find the current carried by the wire and the power rating of the heater.**Solution:**Using the formula \( \Delta V = IR \), we calculate the current:\[I = \frac{\Delta V}{R} = \frac{120 \, \text{V}}{7.00 \, \Omega} = \underline{\hspace{1cm}} \, \text{A}\]To find the power rating, use the expression \( \mathscr{P} = I^2R \):\[\mathscr{P} = I^2(7.00 \, \Omega) = \underline{\hspace{1cm}} \, \text{W}\]**What If?**What if the heater were accidentally connected to a 240 V supply? (This is difficult to do because the shape and orientation of the metal contacts in 240 V plugs are different from those in 120 V plugs.) How would this affect the current carried by the heater and the power rating of the heater?**Answer:**If we doubled the applied potential difference, Equation 27.8 tells us that the current would double. According to Equation 27.23, \( \mathscr{P} = (\Delta V)^2/R \), the power would be four times larger. **Exercise 27.7****Hints:** Getting Started | I'm StuckWhat if we have another heater rated at 120 V with power 2.0 kW?(A) What is the resistance of the heater, and the current when it is under normal operation?- \( R = \) [_____] \(\Omega\)- \( I = \) [_____] A(B) If we connect it to a 240 V source, assuming that it still works, what will be the actual power consumption now (in kW)?- [_____] kW

Answered: Image /qna-images/answer/6040debf-8037-4d26-9499-472c69f1e6b0.jpg

Exercise 27.7 Hints: Getting Started | I'm Stuck What if we have another heater rated at 120 V with power 2.0 kW? (A) What is the resistance of the heater, and the current when it is under normal operation? R = Ω I = A (B) If we connect it a 240 V source, assuming that it still works, what will be the actual power consumption now (in kW)? kW

Exercise 27.7 Hints: Getting Started | I'm Stuck What if we have another heater rated at 120 V with power 2.0 kW? (A) What is the resistance of the heater, and the current when it is under normal operation? R = Ω I = A (B) If we connect it a 240 V source, assuming that it still works, what will be the actual power consumption now (in kW)? kW

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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