Find the instantaneous power. Use image provided "artSubstitute known quantities and solve for the unknown quantity. (cont.)Solving Ohm's law for the instantaneous current givesAv (165 V)sin(50xt)RRand substituting known values givesAv (165 V)sin(50xt)RR(165 V)sin [50x(4.45 x 10-³ s)]= 0.385 A.276 ΩThe unknown quantity to be determined in part (e) is the instantaneous power dissipated by the resistor whent = 4.45 x 10-³ s. The instantaneous power dissipated by the resistor is given by P = 1²R.What instantaneous power is dissipated by the resistor at t = 4.45 x 10-³ s?W

Answered: Image /qna-images/answer/a7b69b3c-cba3-4294-bf9a-ac3eb31f1cb6.jpg

Substitute known quantities and solve for the unknown quantity. (cont.) Solving Ohm's law for the instantaneous current gives Av (165 V)sin(50st) R R and substituting known values gives Av (165 V)sin(50xt) R R (165 V)sin [50x(4.45 x 10-³ s)] 276 Ω The unknown quantity to be determined in part (e) is the instantaneous power dissipated by the resistor when t = 4.45 x 10-³ s. The instantaneous power dissipated by the resistor is given by P = 12R. What = = 0.385 A.

Substitute known quantities and solve for the unknown quantity. (cont.) Solving Ohm's law for the instantaneous current gives Av (165 V)sin(50st) R R and substituting known values gives Av (165 V)sin(50xt) R R (165 V)sin [50x(4.45 x 10-³ s)] 276 Ω The unknown quantity to be determined in part (e) is the instantaneous power dissipated by the resistor when t = 4.45 x 10-³ s. The instantaneous power dissipated by the resistor is given by P = 12R. What = = 0.385 A.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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