Exercise 2.8. The number X of milk-chocolate chips and the number Y of dark- chocolate chips in a cookie are independent and have Poisson (A) and Poisson(µ) distributions, respectively. Show that the distribution of X given the total number of chocolate chips X + Y = n is Binomial ( n, You can use without derivation the fact that the sum of independent Poisson random variables is Poisson again: X + Y ~ Poisson(A+ µ).

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Exercise 2.8. The number X of milk-chocolate chips and the number Y of dark-
chocolate chips in a cookie are independent and have Poisson (A) and Poisson(u)
distributions, respectively. Show that the distribution of X given the total number
of chocolate chips X + Y = n is Binomial ( n,
You can use without
derivation the fact that the sum of independent Poisson random variables is Poisson
again: X + Y ~ Poisson(A+ µ).
Transcribed Image Text:Exercise 2.8. The number X of milk-chocolate chips and the number Y of dark- chocolate chips in a cookie are independent and have Poisson (A) and Poisson(u) distributions, respectively. Show that the distribution of X given the total number of chocolate chips X + Y = n is Binomial ( n, You can use without derivation the fact that the sum of independent Poisson random variables is Poisson again: X + Y ~ Poisson(A+ µ).
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