Exercise 2.14. Let A € Mmn (R). For r = {1,...,m} and s € {1,...,m}, let Irs € Mm(R) be the matrix whose rs-component is 1 and all the other ones are equal to 0. Answer the following questions with words: 1. What is Is A ? 2. For rs, what is (Irs + Isr) A ? 3. For rs, what is (1m + Irs + Isr - Irr - Iss) A ? . 4. For rs, what is (1m+cIrs) A, for some c ER ?

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Exercise 2.14. Let A € Mmn (R). For r = {1,...,m} and s € {1,...,m}, let Irs €
Mm (R) be the matrix whose rs-component is 1 and all the other ones are equal to 0.
Answer the following questions with words :
1. What is Is A ?
2. For rs, what is (Irs + Isr) A ?
3. For rs, what is (1m + Irs + Isr - Irr - Iss) A ?
4. For rs, what is (1m+cIrs) A, for some c ER ?
Transcribed Image Text:Exercise 2.14. Let A € Mmn (R). For r = {1,...,m} and s € {1,...,m}, let Irs € Mm (R) be the matrix whose rs-component is 1 and all the other ones are equal to 0. Answer the following questions with words : 1. What is Is A ? 2. For rs, what is (Irs + Isr) A ? 3. For rs, what is (1m + Irs + Isr - Irr - Iss) A ? 4. For rs, what is (1m+cIrs) A, for some c ER ?
Expert Solution
Step 1: Elementary matrix Operations

Given that A space element of M subscript m n end subscript open parentheses straight real numbers close parentheses a n d space I subscript r s end subscript element of M subscript m open parentheses straight real numbers close parentheses space d e n o t e space a space m cross times m space r e a l space m a t r i x space w h o s e space r s space c o m p o n e n t space i s 1 space a n d space o t h e r space c o m p o n e n t space i s space 0.

1) open parentheses I subscript r s end subscript A close parentheses subscript i j end subscript equals open curly brackets table row cell a subscript s j end subscript space comma end cell cell i equals s comma for all j end cell row cell 0 space comma end cell cell i not equal to s comma for all j end cell end table close

2) for r not equal to s comma left parenthesis I subscript r s end subscript plus I subscript s r end subscript right parenthesis A equals I subscript r s end subscript A plus I subscript s r end subscript A

Now open parentheses I subscript r s end subscript A close parentheses subscript i j end subscript equals open curly brackets table row cell a subscript s j end subscript end cell cell for all j end cell row 0 cell i not equal to s comma for all j end cell end table close space a n d space open parentheses I subscript s r end subscript A close parentheses subscript i j end subscript equals open curly brackets table row cell a subscript r j end subscript end cell cell i equals r comma for all j end cell row 0 cell i not equal to r comma for all j end cell end table close

Hence open parentheses open parentheses I subscript r s end subscript plus I subscript s r end subscript close parentheses A close parentheses subscript i j end subscript equals open parentheses I subscript r s end subscript A close parentheses subscript i j end subscript plus open parentheses I subscript s r end subscript A close parentheses subscript i j end subscript equals open curly brackets table row cell a subscript r j end subscript comma w h e n space i equals r space a n d space a subscript s j end subscript space w h e n space i equals s end cell row cell 0 comma o t h e r w i s e end cell end table close

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