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Exercise 2 * The following data can be used to approximate M = (e* + 2x) dx. N, (h) = 1.68394, N () = 1.731370, N, (4) = 1.742984. Assuming M = N, (h) + k,h? + k,h* + k,hs + 0(h®), Find N3 (h). (A) N3 (h) = 1.747180 (B) N3 (h) = 1.746833 (C) N3 (h) = 1.746855 (D) N3 (h) = 1.745218 %3D

Exercise 2 * The following data can be used to approximate M = (e* + 2x) dx. N, (h) = 1.68394, N () = 1.731370, N, (4) = 1.742984. Assuming M = N, (h) + k,h? + k,h* + k,hs + 0(h®), Find N3 (h). (A) N3 (h) = 1.747180 (B) N3 (h) = 1.746833 (C) N3 (h) = 1.746855 (D) N3 (h) = 1.745218 %3D

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Exercise 2 * The following data can be used to approximate M = (e-* + 2x) dx. ) = 1.731370, N, (h) = 1.68394, N, N (4) = 1.742984. Assuming M = N, (h) + k,h? + k,h* + kzh6 + 0(h®), Find N3(h). %3! (A) N3 (h) = 1.747180 (B) N3 (h) = 1.746833 (C) N2 (h) = 1.746855 (D) N3 (h) = 1.745218 %3D %3D А В
Transcribed Image Text:Exercise 2 * The following data can be used to approximate M = (e-* + 2x) dx. ) = 1.731370, N, (h) = 1.68394, N, N (4) = 1.742984. Assuming M = N, (h) + k,h? + k,h* + kzh6 + 0(h®), Find N3(h). %3! (A) N3 (h) = 1.747180 (B) N3 (h) = 1.746833 (C) N2 (h) = 1.746855 (D) N3 (h) = 1.745218 %3D %3D А В
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