. (-1)*+1 47. k=1 (k+1)!

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Where did they get the 1/k^2 from in the answer key?

gence 1CSU.
1
and also note that for k 2 1, (k+1)! > k²,
10.6.47 Note that the absolute value of the kth term is
(k+1)!'
1
1
Now because
k2 *
and thus
(k +1)!
k2
k=1
is a convergent p-series, the given series converges absolutely
by the Comparison Test.
Transcribed Image Text:gence 1CSU. 1 and also note that for k 2 1, (k+1)! > k², 10.6.47 Note that the absolute value of the kth term is (k+1)!' 1 1 Now because k2 * and thus (k +1)! k2 k=1 is a convergent p-series, the given series converges absolutely by the Comparison Test.
(-1)*1
47.
k=1 (k+1)!
k%3D1
Transcribed Image Text:(-1)*1 47. k=1 (k+1)! k%3D1
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